将用户输入与存储在向量中的值进行比较

Question

这是我到目前为止的程序。它编译但在最后一部分卡住并崩溃。我想重复用户的字符串输入并用“****”替换字符串中发现的任何坏词。我的错误很可能在 find_Poop_inSentence。 "Debug Assertion failed. vector subscript out of range"

void find_Poop_inSentence(vector<string> & v1, vector<string> & v2, string sub);

int main()
{
cout << "Howdy partner, tell me some words you don't take kindly to.\n";
vector<string>bad_words;
string word;

while (cin >> word)
{
    cin.ignore();
    bad_words.push_back(word);
    if (word == "exit")
        break;

}
cout << "Ok partner, got it!\n";
cout << "Now say something and I'll repeat it back to you. Don't worry, I'll bleep out the words that you don't like.\n";

word = "";
vector<string> random_sentence; 
while (cin >> word)
{
    cin.ignore();
    random_sentence.push_back(word);
    if (cin.get() == '\n')
        break;

}

find_Poop_inSentence(bad_words, random_sentence, "****");

cout << "You said: ";
for (unsigned int i = 0; i < random_sentence.size(); ++i) {
    cout << ' ' << random_sentence[i];
}
system("Pause");
return 0;
}

void find_Poop_inSentence(vector<string> & v1, vector<string> & v2, string sub) {
int iterOne;
int iterTwo = 0;
int iteratorMax = v2.size();


for (iterOne = 0; iterOne < iteratorMax; iterTwo++) {

    if (v1[iterOne] == v2[iterTwo]) {
        v2[iterTwo] == sub;
    }
    if (iterTwo == iteratorMax ) {
        iterOne++;
        iterTwo = 0;
    }

  }
}

Answer 1

你要做的不仅仅是带问号的部分。即使您设法实现了替换部分，您的代码仍然无法正常工作。

find(bad_words.begin(), bad_words.end(), say_back) != bad_words.end())

find() 搜索前两个参数给出的序列，开始和结束迭代器值。这些是你的 bad_words。 find() 检查第三个参数给出的值的第一次出现，return 迭代器引用第一个找到的值，或者 end() 如果没有找到该值。

因此，如果 bad_words 包含 "Fudge"，并且您将 "Fudge" 键入 say_back，find() 将找到它。

但是，如果您在 say_back 中输入 "Definitely Fudge"，当然 find() 将找不到它。因为 bad_words 中的 none 恰好包含 "Definitely Fudge"。 find() 搜索完全匹配。

因此，如果您希望 "replace any bad words found in the" say_back 字符串，这将不起作用。

在您开始考虑替换 say_back 中的任何 bad_words 之前，您需要找出正确的算法。您需要找到 say_back 中的每个单词，然后检查 bad_words.

中的每个单词

在您可以正确实施搜索算法之前，弄清楚如何替换您在 bad_words 中找到的东西，从某种意义上说，就是本末倒置。

你得先想清楚；如果需要，您可以随时 talk to your rubber duck.

Answer 2

感谢我的朋友 Ivan Drago 我能够解决这个问题。

void find_Poop_inSentence(vector<string> & v1, vector<string> & v2, string sub);

int main()
{
cout << "Howdy partner, tell me some words you don't take kindly to.\n";
vector<string>bad_words;
string word;

while (cin >> word)
{
    //cin.ignore();
    bad_words.push_back(word);
    if (word == "exit")
        break;

}
cout << "Ok partner, got it!\n";
cout << "Now say something and I'll repeat it back to you. Don't worry, I'll bleep out the words that you don't like.\n";
cout << "Push enter twice when done.\n";

word = "";
vector<string> random_sentence;
while (cin >> word)
{
    //cin.ignore();
    random_sentence.push_back(word);
    if (cin.get() == '\n')
        break;

}

find_Poop_inSentence(bad_words, random_sentence, "****");

cout << "You said: ";
for (unsigned int i = 0; i < random_sentence.size(); ++i) {
    cout << ' ' << random_sentence[i];
}
system("Pause");
return 0;
}

void find_Poop_inSentence(vector<string> & v1, vector<string> & v2, string sub) {

for (unsigned int i = 0; i < v1.size(); i++) {

    for (unsigned int j = 0; j < v2.size(); j++) {
        if (v1[i] == v2[j]) {
            v2[j] = sub;
        }

    }
  }

}

将用户输入与存储在向量中的值进行比较

Compare user input with values stored in vector

c++

debugging

user-input

vector

findandmodify