如何在多个文件输入中将数据插入数据库？

Question

我有一个代码可以让一个人通过表单上传多张图片。

问题是，图片可以很好地上传到服务器，但不确定如何将图片发送到数据库中。

PHP:

        else{ // No error found! Move uploaded files 
            if(move_uploaded_file($_FILES["files"]["tmp_name"][$f], $targetscreenshots.$name)) 

            $count++; // Number of successfully uploaded file

        }

我应该把下面的代码放在哪里？

        {
mysql_query("INSERT into Colleges (`files`) VALUES ('$files')"); // inserting data if file is moved 
    echo "Your screenshots have been uploaded successfully!"
        }

Answer 1

您缺少负责修改数据库的代码，建议您阅读一些教程，例如this one。我还没有测试过，但至少看起来它包含了所有需要的步骤。

Answer 2

$files = $_FILES["files"]["tmp_name"][$f]

只需在数据库中插入文件路径或名称

Answer 3

这是我在脚本中使用的自己的代码。

        <?php
             $upath="../images/";
            //uploads is the name of file array that is being uploaded.
        foreach ($_FILES['uploads']['name'] as $key=>$file) {
            $target = $upath.$file;
            $path=substr($target,3);
            // echo $path; THIS CAN BE STORED DIRECTLY TO THE DATABASE
            move_uploaded_file($_FILES['uploads']['tmp_name'][$key], $target)
            or die();
            mysql_query(**YOUR INSERT QUERY HERE. IT WONT BE EXECUTED IF IMAGE IS NOT UPLOADED PROPERLY.**)or die(mysql_error());

        }

        ?>

我看了你的评论，所以我给出了这个答案...如果我误解了你的问题，请纠正我。

如何在多个文件输入中将数据插入数据库？

How to insert data into database in a multiple file input?

php

image-uploading

multiple-file-upload