为什么这句话要去掉"unreferenced function argument warning"呢？

Question

在 SDCC 编译器用户指南中我阅读了以下内容：

void to_buffer( unsigned char c )
{
c; // to avoid warning: unreferenced function argument
__asm
; save used registers here.
; If we were still using r2,r3 we would have to push them here.
; if( head != (unsigned char)(tail-1) )
mov a,_tail
dec a
xrl a,_head
; we could do an ANL a,#0x0f here to use a smaller buffer (see below)
jz t_b_end$
;
; buf[ head++ ] = c;
mov a,dpl ; dpl holds lower byte of function argument
mov dpl,_head ; buf is 0x100 byte aligned so head can be used directly
mov dph,#(_buf>>8)
movx @dptr,a
inc _head
; we could do an ANL _head,#0x0f here to use a smaller buffer (see above)
t_b_end$:
; restore used registers here
__endasm;
}

不明白"c; // to avoid warning: unreferenced function argument"这句话是什么意思，难道是SDCC的特殊用法？还是C语言的特殊用法？

Answer 1

如果您有一个您不使用的传入函数参数，编译器往往会警告您。在您的情况下， c; 是一个 void 操作来访问变量并避免警告。它类似于

 int func(char c)
 {
  (void)c;
  //c is never used in the function
 }

FWIW，在 gcc 中，要启用警告，使用 -Wunused-parameter 选项。（在 -Wextra 中启用）

为什么这句话要去掉"unreferenced function argument warning"呢？

Why does this sentence eliminate the "unreferenced function argument warning"?

c

warnings

compiler-warnings

sdcc