SQL 根据注释单元格的多条件测试生成分数列

Question

基本上我有一个 table 和一个注释列，我想生成一个查找一些条件的列，并根据查看每个注释时满足的条件数得出一个分数。我可能会以错误的方式解决这个问题，所以请随意切线。

目前查询：

SELECT
SUM(
    SUM(case when notes like '%Tuna%' THEN 1 ELSE 0 END)
    SUM(case when notes like '%apple%' THEN 1 ELSE 0 END)
    SUM(case when notes like '%burrito' THEN 1 ELSE 0 END)
            --      ) as score
,Name
,Date
,Notes
FROM food_jrnl

示例 table food_jrnl:

Name    Date    Note
Peter   6/1/2016    Just mountain Dew and cheatos
Jimmy   5/25/2016   Chocolate cake, cheesy potatoes and ketchup
Sophie  5/16/2016   just grits and tuna!!
Bianca  5/9/2016    Chocolate milk, Ahi tuna, Gala apple
Sam 4/23/2016   Tuna salad
Josh    1/10/2016   Had a banana and apple with orange juice

我希望创造的：

Score   Name    Date    Note
0   Peter   6/1/2016    Just mountain Dew and cheatos
0   Jimmy   5/25/2016   Chocolate cake, cheesy potatoes and ketchup
1   Sophie  5/16/2016   just grits and tuna!!
2   Bianca  5/9/2016    Chocolate milk, Ahi tuna, Gala apple
1   Sam 4/23/2016   Tuna salad
0   Josh    1/10/2016   Had a banana and apple with orange juice

Answer 1

实际上你不需要为此使用 sum:

SELECT
    case when notes like '%Tuna%' THEN 1 ELSE 0 END +
    case when notes like '%apple%' THEN 1 ELSE 0 END +
    case when notes like '%burrito' THEN 1 ELSE 0 END as score
    ,Name
    ,Date
    ,Notes
FROM food_jrnl

SQL 根据注释单元格的多条件测试生成分数列

SQL generate score column from multi-condition test on a notes cell

sql

select

multiple-conditions