为什么我的自定义迭代器需要基于范围的 for 循环调用运算符？

Question

Link 到 mcve.

我们将矩阵定义为可按行和按列迭代。下面是逐行迭代器的实现：

template<class Real>
class RowIterator {
public:
    RowIterator() { }
    RowIterator(Real* begin, size_t rows, size_t cols) : begin(begin), rows(rows), cols(cols) { }

    Real* operator*() const { return begin; }
    Real& operator[](size_t col) const { return begin[col]; }

    bool operator!=(const RowIterator& it) const { return begin != it.begin; }
    RowIterator& operator++() { begin += cols; --rows; return *this; }

private:
    Real* begin;
    size_t rows, cols;
};

迭代矩阵是使用 Range 对象实现的，定义如下：

namespace details
{

template<class Iterator>
struct Range {
    Iterator begin, end;
    Range() { }
    Range(Iterator begin, Iterator end) : begin(begin), end(end) { }
};

template<class Iterator>
Iterator begin(const Range<Iterator>& range) { return range.begin; }
template<class Iterator>
Iterator end(const Range<Iterator>& range) { return range.end; }

}

using details::Range;
template<class Iterator>
Range<Iterator> make_range(Iterator begin, Iterator end) { return Range<Iterator>(begin, end); }

这基本上就是我们的使用代码：

Range<RowIterator<float>> make_row_range(float* mat, size_t rows, size_t cols) {
    return make_range(
        RowIterator<float>(mat, rows, cols),
        RowIterator<float>(mat + rows * cols, 0, cols));
}

int main() {
    size_t rows = 4, cols = 6;
    float* mat = new float[rows * cols];
    for(size_t i = 0; i < rows * cols; ++i)
        mat[i] = (float)i;
    auto rowrange = make_row_range(mat, rows, cols);

    // this loop works as expected
    std::cout << "begin, end" << std::endl;
    for(auto b = begin(rowrange), e = end(rowrange); b != e; ++b) {
        // using RowIterator<T>::operator[](size_t)
        std::cout << "start of row: " << b[0] << std::endl;
    }

    // this loop produces confusing compiler errors
    std::cout << "range based" << std::endl;
    for(auto row : rowrange) {                        // this is line 42
        // row is of type float*
        std::cout << "start of row: " << row[0] << std::endl;
    }
    return 0;
}

我编译上面的 MCVE 并得到以下编译器错误：

Visual Studio 2013（全部在第 42 行）：

error C2064: term does not evaluate to a function taking 0 arguments
error C3536: '$S2': cannot be used before it is initialized
error C3536: '$S3': cannot be used before it is initialized
error C2100: illegal indirection
error C2440: 'initializing' : cannot convert from 'int' to 'float *'

GCC 5.1（第 42 行）：

error: no match for call to '(RowIterator<float>) ()'

Clang 3.7.0（第 42 行）：

error: type 'RowIterator<float>' does not provide a call operator
note: when looking up 'begin' function for range expression of type 'details::Range<RowIterator<float> >'

所有编译器都在搜索调用运算符。 为什么？ As I understand, the above iterator provides the minimal interface for ranged loops and it works when using the syntactical equivalence code from cppreference.com.

Answer 1

在写这个问题时我想到了解决方案（rubber SO debugging?）：编译器首先检查成员 Range::begin 和 Range::end并尝试调用那些导致丢失的调用操作符的方法。 None 的测试编译器在他们的错误消息中清楚地指出了这一点 [1]。解决方法是简单地重命名它们：

namespace range
{

template<class Iterator>
struct Range {
    // "begin" and "end" have ultra-special meaning in this context!!!
    Iterator range_begin, range_end;
    Range() { }
    Range(Iterator begin, Iterator end) : range_begin(begin), range_end(end) { }
};

template<class Iterator>
Iterator begin(const Range<Iterator>& range) { return range.range_begin; }
template<class Iterator>
Iterator end(const Range<Iterator>& range) { return range.range_end; }

}

class Range 的要求定义明确（来源：cppreference.com，强调我的）：

begin_expr and end_expr are defined as follows:

1 If range_expression is an expression of array type, then begin_expr is __range and end_expr is (__range + __bound), where __bound is the number of elements in the array (if the array has unknown size or is of an incomplete type, the program is ill-formed)

2 If range_expression is an expression of a class type C that has a member named begin and/or a member named end (regardless of the type or accessibility of such member), then begin_expr is __range.begin() and end_expr is __range.end();

3 Otherwise, begin_expr is begin(__range) and end_expr is end(__range), which are found via argument-dependent lookup (non-ADL lookup is not performed).

[1]：Clang 实际上接近了，尽管它的信息也含糊不清：我认为它是 (adl) 查找 details::begin(Range) 而不是直视 Range::begin.

为什么我的自定义迭代器需要基于范围的 for 循环调用运算符？

Why does my custom iterator require a call operator in range based for loops?

c++

ranged-loops