interpolate/extrapolate 缺少 python 中的日期？

Question

假设我有以下数据框

bb = pd.DataFrame(data = {'date' :['','','','2015-09-02', '2015-09-02', '2015-09-03','','2015-09-08', '', '2015-09-11','2015-09-14','','' ]})     
bb['date'] = pd.to_datetime(bb['date'], format="%Y-%m-%d")

我想线性插值和外插以填充缺失的日期值。我使用了以下代码，但它没有改变任何东西。我是 pandas 的新手。请帮忙

bb= bb.interpolate(method='time')

Answer 1

要进行推断，您必须使用 bfill() 和 ffill()。缺失值将由后向（或前向）值分配。

要进行线性插值，您必须使用函数 interpolate 但日期需要转换为数字：

import numpy as np
import pandas as pd
from datetime import datetime

bb = pd.DataFrame(data = {'date' :['','','','2015-09-02', '2015-09-02', '2015-09-03','','2015-09-08', '', '2015-09-11','2015-09-14','','' ]})     
bb['date'] = pd.to_datetime(bb['date'], format="%Y-%m-%d")     

# convert to seconds
tmp = bb['date'].apply(lambda t: (t-datetime(1970,1,1)).total_seconds())
# linear interpolation
tmp.interpolate(inplace=True)    
# back convert to dates
bb['date'] = pd.to_datetime(tmp, unit='s') 
bb['date'] = bb['date'].apply(lambda t: t.date())
# extrapolation for the first missing values
bb.bfill(inplace='True')

print bb

结果：

         date
0  2015-09-02
1  2015-09-02
2  2015-09-02
3  2015-09-02
4  2015-09-02
5  2015-09-03
6  2015-09-05
7  2015-09-08
8  2015-09-09
9  2015-09-11
10 2015-09-14
11 2015-09-14
12 2015-09-14

interpolate/extrapolate 缺少 python 中的日期？

interpolate/extrapolate missing dates in python?

python

interpolation

scipy

pandas

extrapolation