PHP 日期差异只计算天数

Question

我的日期是 day::month::year-h-m-s 格式，现在我只想计算这两个日期之间的天数？

Answer 1

你可以这样做

  $date1 = new DateTime(date('Y-m-d', strtotime("2013-08-07 13:00:00")));
  $date2 = new DateTime(date('Y-m-d', strtotime("2013-08-08 12:00:00")));
  echo $date1->diff($date2)->days;

Answer 2

PHP:

<?php

$otherday = date_create("01-05-2015");
$today= date_create(date("d-m-Y"));

$days = $today->diff($otherday);

echo $days->format("%R%a");

?>

%R 表示 (+) 或 (-) 你只能使用 %a.

Answer 3

试试这个

$dateDiff=date_diff(date_create($date1),date_create($date2)); 
echo $dateDiff->format("%a days");

Answer 4

试试这个

$fisrstDate = new DateTime(date('Y-m-d', strtotime($fisrstDate)));
$secondDate = new DateTime(date('Y-m-d', strtotime($secondDate)));
echo $fisrstDate->diff($secondDate)->days;

PHP 日期差异只计算天数

PHP date difference calculate onlys for days

php

datediff