创建 MultiUserChat 时获取 NoResponseException

Question

我正在尝试使用 XMPP Smack Api(4.1.4) 创建多用户聊天。我已经使用

建立了登录连接

XMPPTCPConnectionConfiguration.Builder configBuilder = XMPPTCPConnectionConfiguration.builder();
configBuilder.setSecurityMode(ConnectionConfiguration.SecurityMode.disabled);
    configBuilder.setResource(RESOURCE);
    configBuilder.setServiceName(DOMAIN);
    configBuilder.setHost(HOST);
    XMPPTCPConnection connection = new XMPPTCPConnection(configBuilder.build());
    connection.addConnectionListener(connectionListener);

AsyncTask<Void, Void, Boolean> connectionThread = new AsyncTask<Void, Void, Boolean>() {
        @Override
        protected Boolean doInBackground(Void... arg0) {
            try {
                connection.connect();
                if(connection != null) {
                PingManager mPingManager = PingManager.getInstanceFor(connection);
                mPingManager.setDefaultPingInterval(1000 * 50);
                mPingManager.setPingInterval(1000 * 50);
                connection.setPacketReplyTimeout(1000 * 50);
                mPingManager.registerPingFailedListener(new PingFailedListener() {
                @Override
                public void pingFailed() {
                    // TODO Auto-generated method stub
                    Log.e("PING", "ping failed");
                    // AGain Reconnecting code here..
            }
        });
    }
            } catch (IOException | SmackException | XMPPException e) {
                Log.d(LOCAL_TAG, "connectConnection  exc: "+e.getMessage());
            }
            return null;
        }
    };
    connectionThread.execute();

连接成功。连接后，我正在尝试使用

创建群聊

    try {
        SharedPreferences mPreferences = context.getSharedPreferences("App_Pref", Context.MODE_PRIVATE);
        String userJid = userJidAddress(with local ip);
        String userName =  "Test5";
        Log.d(LOCAL_TAG, "createGroupChat  jid: "+userJid+" -- connection.getServiceName(): "+connection.getServiceName());

        MultiUserChatManager manager = MultiUserChatManager.getInstanceFor(connection);
        MultiUserChat muc = manager.getMultiUserChat(userJid);

        muc.create("InstantRoom");

        Log.d(LOCAL_TAG, "createGroupChat  -- Group CEATED Successfully ");
        Form form = muc.getConfigurationForm();
        Form submitForm = form.createAnswerForm();

        List<FormField> fields = form.getFields();
        Log.d(LOCAL_TAG, "createGroupChat  -- fields.size(): "+fields.size());
        for (int i = 0; i < fields.size(); i++) {
            FormField field = (FormField) fields.get(i);
            if (!FormField.Type.hidden.equals(field.getType()) && field.getVariable() != null) {
                submitForm.setDefaultAnswer(field.getVariable());
            }
        }

        List owners = new ArrayList();
        owners.add("test5"+connection.getServiceName());
        owners.add("test7"); //Another user
        submitForm.setAnswer("muc#roomconfig_roomowners", owners);
        submitForm.setAnswer("muc#roomconfig_persistentroom", true);
        muc.sendConfigurationForm(submitForm);
        muc.join("InstantRoom");

    }
    catch(Exception e){
        Log.d(LOCAL_TAG, "createGroupChat --  Exception: "+e.toString());
    }

但是在创建组时，我得到一个异常

    "org.jivesoftware.smack.SmackException$NoResponseException: No response received within reply timeout. Timeout was 50000ms (~50s). Used filter: AndFilter: (FromMatchesFilter (full): test5@172.21.4.199/instantroom, StanzaTypeFilter: org.jivesoftware.smack.packet.Presence)."

如果我增加 PingIntervals 和 PacketReplyTimeout 毫秒，那么我会收到一条消息

"Thread[5,tid=4403,WaitingInMainSignalCatcherLoop,Thread*=0xb8e933a8,peer=0x12c000a0,"Signal Catcher"]：响应信号 3".

没有那个例外，应用程序设置为自动强制关闭。希望如此，我在 muc.create("InstantRoom") 行收到异常，因为我无法在该行之后获取日志。任何人都可以帮助我弄清楚我做错了什么以及为什么我会收到此错误以及如何在此之后继续。提前致谢。

Answer 1

这两行是错误的

 MultiUserChat muc = manager.getMultiUserChat(userJid);

        muc.create("InstantRoom");

当你得到一个 MUC 时，你必须得到一个 NAME（这样经理可以告诉你是否已经存在）。

确实，当您创建 muc 时，您必须输入用户名。

所以

String myMUCName = "InstantRoom";
String myMUCService = "conference.myServer";
String myMUCfullName = myMUCName + "@" + myMUCService;
MultiUserChat muc = manager.getMultiUserChat(myMUCfullName);
muc.create(userName);

（如果这不能解决您的问题，请在确认该服务已在服务器上注册后告诉我 - 也许您在表单上会有额外的问题）

创建 MultiUserChat 时获取 NoResponseException

Getting NoResponseException while creating MultiUserChat

android

exception

smack