使用 mutate_ 进行标准评估以按组计算百分比
Standard evaluation with mutate_ to calculate percentages by group
我正在尝试使用 dplyr
的标准评估来计算作为两个分组变量函数的百分比。问题出在我的mutate_ statement
。
这是一个数据集:
structure(list(
var1 = structure(c(2L, 1L, 1L, 2L, 1L, 2L, 1L,
2L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 1L,
2L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 2L,
2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 2L, 1L, 2L, 1L,
2L, 2L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 1L,
1L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L,
2L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 2L, 1L, 1L
),
.Label = c("No", "Yes"), class = "factor"),
var2 = structure(c(2L, 2L, 1L, 2L,
2L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 2L, 2L, 1L, 1L, 2L, 1L, 2L,
1L, 2L, 2L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L,
1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 2L, 2L, 1L, 2L,
2L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 2L, 1L, 2L, 2L, 1L, 1L, 1L,
2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 2L, 1L,
1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 2L
),
.Label = c("Female", "Male"), class = "factor")),
.Names = c("var1", "var2"), row.names = c(NA, -100L), class = "data.frame")
这是我正在使用的代码:
for_plots = function(data, var1, var2){
grouped_data = data %>% group_by_(var1, var2) %>%
summarise_(n_in_group = ~n()) %>%
mutate_(.dots = setNames(list(
interp(quote(n_in_group / sum(n_in_group, na.rm = TRUE) * 100),
n_in_group = as.name(n_in_group)))
))
return(grouped_data)
}
当我 运行 代码时,我收到一个错误:
Error in setNames(list(interp(quote(n_in_group/sum(n_in_group, na.rm = TRUE) * :
argument "nm" is missing, with no default
有什么想法吗?
下面是一些基于@Frank 回复的代码:
for_plots = function(data, var1, var2) {
grouped_data = data %>% group_by_(var1, var2) %>%
summarise_(n_in_group = ~n()) %>%
mutate(percent = (n_in_group / sum(n_in_group, na.rm = TRUE)) * 100)
return(grouped_data)
}
我正在尝试使用 dplyr
的标准评估来计算作为两个分组变量函数的百分比。问题出在我的mutate_ statement
。
这是一个数据集:
structure(list(
var1 = structure(c(2L, 1L, 1L, 2L, 1L, 2L, 1L,
2L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 1L,
2L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 2L,
2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 2L, 1L, 2L, 1L,
2L, 2L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 1L,
1L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L,
2L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 2L, 1L, 1L
),
.Label = c("No", "Yes"), class = "factor"),
var2 = structure(c(2L, 2L, 1L, 2L,
2L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 2L, 2L, 1L, 1L, 2L, 1L, 2L,
1L, 2L, 2L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L,
1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 2L, 2L, 1L, 2L,
2L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 2L, 2L, 1L, 2L, 2L, 1L, 1L, 1L,
2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 2L, 1L,
1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 2L, 2L
),
.Label = c("Female", "Male"), class = "factor")),
.Names = c("var1", "var2"), row.names = c(NA, -100L), class = "data.frame")
这是我正在使用的代码:
for_plots = function(data, var1, var2){
grouped_data = data %>% group_by_(var1, var2) %>%
summarise_(n_in_group = ~n()) %>%
mutate_(.dots = setNames(list(
interp(quote(n_in_group / sum(n_in_group, na.rm = TRUE) * 100),
n_in_group = as.name(n_in_group)))
))
return(grouped_data)
}
当我 运行 代码时,我收到一个错误:
Error in setNames(list(interp(quote(n_in_group/sum(n_in_group, na.rm = TRUE) * : argument "nm" is missing, with no default
有什么想法吗?
下面是一些基于@Frank 回复的代码:
for_plots = function(data, var1, var2) {
grouped_data = data %>% group_by_(var1, var2) %>%
summarise_(n_in_group = ~n()) %>%
mutate(percent = (n_in_group / sum(n_in_group, na.rm = TRUE)) * 100)
return(grouped_data)
}