python 中用于多类分类的 XGBClassifier 交叉验证

Question

我正在尝试使用改编自 http://www.analyticsvidhya.com/blog/2016/03/complete-guide-parameter-tuning-xgboost-with-codes-python/

的以下代码对 XGBClassifier 执行交叉验证以解决多重 class class 化问题

import numpy as np
import pandas as pd
import xgboost as xgb
from xgboost.sklearn import  XGBClassifier
from sklearn.preprocessing import LabelEncoder
from sklearn import cross_validation, metrics
from sklearn.grid_search import GridSearchCV


def modelFit(alg, X, y, useTrainCV=True, cvFolds=5, early_stopping_rounds=50):
    if useTrainCV:
        xgbParams = alg.get_xgb_params()
        xgTrain = xgb.DMatrix(X, label=y)
        cvresult = xgb.cv(xgbParams,
                      xgTrain,
                      num_boost_round=alg.get_params()['n_estimators'],
                      nfold=cvFolds,
                      stratified=True,
                      metrics={'mlogloss'},
                      early_stopping_rounds=early_stopping_rounds,
                      seed=0,
                      callbacks=[xgb.callback.print_evaluation(show_stdv=False),                                                               xgb.callback.early_stop(3)])

        print cvresult
        alg.set_params(n_estimators=cvresult.shape[0])

    # Fit the algorithm
    alg.fit(X, y, eval_metric='mlogloss')

    # Predict
    dtrainPredictions = alg.predict(X)
    dtrainPredProb = alg.predict_proba(X)

    # Print model report:
    print "\nModel Report"
    print "Classification report: \n"
    print(classification_report(y_val, y_val_pred))
    print "Accuracy : %.4g" % metrics.accuracy_score(y, dtrainPredictions)
    print "Log Loss Score (Train): %f" % metrics.log_loss(y, dtrainPredProb)
    feat_imp = pd.Series(alg.booster().get_fscore()).sort_values(ascending=False)
    feat_imp.plot(kind='bar', title='Feature Importances')
    plt.ylabel('Feature Importance Score')


# 1) Read training set
print('>> Read training set')
train = pd.read_csv(trainFile)

# 2) Extract target attribute and convert to numeric
print('>> Preprocessing')
y_train = train['OutcomeType'].values
le_y = LabelEncoder()
y_train = le_y.fit_transform(y_train)
train.drop('OutcomeType', axis=1, inplace=True)

# 4) Extract features and target from training set
X_train = train.values

# 5) First classifier
xgb = XGBClassifier(learning_rate =0.1,
                    n_estimators=1000,
                    max_depth=5,
                    min_child_weight=1,
                    gamma=0,
                    subsample=0.8,
                    colsample_bytree=0.8,
                    scale_pos_weight=1,
                    objective='multi:softprob',
                    seed=27)

modelFit(xgb, X_train, y_train)

其中 y_train 包含从 0 到 4 的标签。但是，当我运行这段代码时，我从 xgb.cv 函数 xgboost.core.XGBoostError: value 0for Parameter num_class should be greater equal to 1 得到以下错误。在 XGBoost 文档上，我读到在 multiclass 情况下 xgb 从目标向量中的标签推断 classes 的数量，所以我不明白发生了什么。

Answer 1

您必须将参数“num_class”添加到 xgb_param 字典中。参数说明和您在上面提供的 link 的评论中也提到了这一点。

python 中用于多类分类的 XGBClassifier 交叉验证

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