使用输入过滤器在 EditText android 中阻止数字

Block numeric in EditText android using input filter

我想通过不在 xml 中的输入过滤器以编程方式执行此操作,例如 - android:digits="aA".

这是我的代码

public static void RemoveCharacter(EditText text, String character, int length) {
final String blockCharacterSet = character;
// final String blockCharacterSet = "\"+[]&~#^|$%*!@/()-'\\":;,?{}=!$^';,?×÷<>{}€£¥₩%~`¤♡♥_|《》¡¿°•○●□■◇◆♧♣▲▼▶◀↑↓←→☆★▪:-);-):-D:-(:'(:O\";
InputFilter[] filter1 = new InputFilter[2];
filter1[0] = new InputFilter() {
    @Override
    public CharSequence filter(CharSequence source, int start, int end,
                               Spanned dest, int dstart, int dend) {
        if (source != null && blockCharacterSet.contains(("" + source))) {
            return "";
        }
        return null;
    }
};
filter1[1] = new InputFilter.LengthFilter(length);


text.setFilters(filter1);

}

它完全适用于 Moto G、nexus 设备,但不适用于三星设备。

尝试使用以下代码添加您选择的输入类型,它将起作用:

your_editText.setInputType(InputType.TYPE_CLASS_TEXT | 
    InputType.TYPE_TEXT_VARIATION_PASSWORD);

好吧,如果你真的想用 InputFilter 来做,它会比那复杂一点。

不同的键盘有很大不同,所以我猜你的解决方案不适用于 Swype/Swift 键盘。

可能尝试使用这样的东西:

    final Set<Character> blockSet = new HashSet<>();
    blockSet.addAll(Arrays.asList('1', '2', '3', '4','5', '6', '7', '8', '9', '0'));

    InputFilter filter = new InputFilter() {
        @Override
        public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
            for (int i = start; i < end; i++) {
                if (Character.isDigit(source.charAt(i))) {
                    char[] v = new char[end - start];
                    TextUtils.getChars(source, start, end, v, 0);
                    String s = new String(v);

                    if (source instanceof Spanned) {
                        CharSequence sp = new SpannableString(s);
                        TextUtils.copySpansFrom((Spanned) source,
                                start, end, null, (Spannable) sp, 0);

                        boolean containsDigit = true;
                        while (containsDigit) {
                            containsDigit = false;
                            for (int j = 0; j < sp.length(); j++) {
                                if (blockSet.contains(sp.charAt(j))) {
                                    sp = TextUtils.concat(sp.subSequence(0, j), sp.subSequence(j + 1, sp.length()));
                                    containsDigit = true;
                                    break;
                                }
                            }
                        }

                        return sp;
                    } else {
                        s = s.replaceAll("\d", "");
                        return s;
                    }
                }
            }
            return null; // keep original
        }
    };