Adobe Animate CC WebGL 翻转状态

Question

我正在创建一个 WebGL canvas 并且我正在尝试使用 onmousemove 片段为动画剪辑按钮创建鼠标悬停。

首先我将按钮的滚动状态设置为不可见，如下所示：

this.YesHOT.setVisible(false);

然后我使用 onmousemove 函数使其在按钮上方时可见：

canvas.onmousemove = function(e) { 
    var boundingRect = this.Yes.getBounds(this);
    if(isMouseOverSymbol(e.offsetX, e.offsetY, boundingRect)) {    
        this.YesHOT.setVisible(true);
    }
}.bind(this);

//Function to check whether the specified point lies within the rect.
function isMouseOverSymbol(pointX, pointY, rect) {
    if(rect.left <= pointX && pointX <= rect.left + rect.width)
        if(rect.top <= pointY && pointY <= rect.top + rect.height)
            return true;
    return false;
}

这行得通，但是翻滚状态仍然可见并且不会关闭。我如何让它关闭？

Answer 1

您从未真正拨打过 this.YesHOT.setVisible(false) 电话。如果我理解你的意图，代码应该是这样的：

canvas.onmousemove = function(e) { 
    var boundingRect = this.Yes.getBounds(this);
    // if mouse cursor is over the "hot" area, show effect. Otherwise hide.
    this.YesHOT.setVisible(isMouseOverSymbol(e.offsetX, e.offsetY, boundingRect));
}.bind(this);

// also hide the effect when mouse completely leaves the canvas
canvas.onmouseleave = function () {
    this.YesHOT.setVisible(false);
}.bind(this);

Adobe Animate CC WebGL 翻转状态

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