为什么我的 ajaxForm 的成功函数没有被调用？

Question

我有一个表单正在通过 AJAX 在 fancybox 中加载。使用 ajaxForm 提交表单，并将数据保存到数据库中。我遇到的唯一问题是没有调用 ajaxForm 的 'success' 函数。

网络选项卡中的呼叫响应；

<script>
$(document).ready(function() {

// submit form
$('#edit_letting_task').ajaxForm({ 
dataType:  'json',
success:    processJsonEditLettingTask
});

function processJsonEditLettingTask(data) { 
    // 'data' is the json object returned from the server 
    alert(data.message); 
}

});
</script>

    { "message": "Test" }

edit_letting_task.php代码（原始代码）；

<?php

require_once('../inc/app_top_cron.php');

?>

<script>
$(document).ready(function() {

// submit form
$('#edit_letting_task').ajaxForm({ 
dataType:  'json',
success:    processJsonEditLettingTask
});

function processJsonEditLettingTask(data) { 
    // 'data' is the json object returned from the server 
    alert(data.message); 
}

});
</script>

    <?php

// process form

if (!empty($_POST)) {

// define and escape each POST as a variable

foreach ($_POST as $key => $value) {

if (!empty($value)) {

${$key} = mysqli_real_escape_string($con, PrepareInput($value));

}
}

// insert data into database

$sql="UPDATE letting_task SET 
letting_task_status = '$letting_task_status',
letting_task_notes = '$letting_task_notes'
WHERE letting_task_id = '$letting_task_id'
";

if (!mysqli_query($con, $sql)) {
  die('Error Inserting Letting Task Data into Database: ' . mysqli_error($con));
} else {
  echo '{ "message": "Test" }';
}

} else {

// define and escape each GET as a variable

if (!empty($_GET)) {

foreach ($_GET as $key => $value) {

if (!empty($value)) {

${$key} = mysqli_real_escape_string($con, PrepareInput($value));

}
}
}

$letting_task_query = mysqli_query($con, "SELECT * FROM letting_task WHERE letting_task_id='" . $letting_task_id . "'") or die(mysql_error());
$letting_task_details = mysqli_fetch_array( $letting_task_query );

// display form

echo '<form id="edit_letting_task" name="edit_letting_task" action="' . SITE_AJAX . 'edit_letting_task.php" method="post">';

echo '<input type="hidden" id="letting_task_id" name="letting_task_id" value="' . $letting_task_id . '">';

// letting task details

echo '<fieldset>
<legend>' . $letting_task_details['letting_task_name'] . '</legend>

<table class="nobord">';

echo '<tr>
    <td><label for="letting_task_status">Status:</label></td>
    <td>';

echo '<select id="letting_task_status" name="letting_task_status" required>';

$letting_task_status_query = mysqli_query($con, "SELECT * FROM letting_task_status ORDER BY letting_task_status_id ASC"); 
while ($letting_task_status_row = mysqli_fetch_array($letting_task_status_query)) {

if ($letting_task_status_row['letting_task_status_id'] == $letting_task_details['letting_task_status']) { $selected = ' selected'; } else { $selected = ''; }

echo '<option value="' . $letting_task_status_row['letting_task_status_id'] . '"' . $selected . '>' . $letting_task_status_row['letting_task_status_name'] . '</option>';

} 

echo '</select>'; 
echo '</td></tr>';

echo '<tr>
<td><label for="letting_task_notes">Notes:</label></td>
<td><textarea id="letting_task_notes" name="letting_task_notes" rows="6" cols="40">' . $letting_task_details['letting_task_notes'] . '</textarea></td>
</tr>';

echo '</table>

</fieldset>';

// actions

echo '<fieldset><legend>Actions</legend>
<table class="nobord">';

echo '<tr><td><input type="submit" value="Save"></td></tr>';
echo '</table>
  </fieldset>';

echo '</form>';

}

mysqli_close($con);

?>

edit_letting_task.php代码（html输出）；

<script>
$(document).ready(function() {

// submit form
$('#edit_letting_task').ajaxForm({ 
dataType:  'json',
success:    processJsonEditLettingTask
});

function processJsonEditLettingTask(data) { 
    // 'data' is the json object returned from the server 
    alert(data.message); 
}

});
</script>

    <form id="edit_letting_task" name="edit_letting_task" action="https://www.property-system-uk.com/admin-area/ajax/edit_letting_task.php" method="post"><input type="hidden" id="letting_task_id" name="letting_task_id" value="1"><fieldset>
<legend>Application to let received</legend>

<table class="nobord"><tr>
    <td><label for="letting_task_status">Status:</label></td>
    <td><select id="letting_task_status" name="letting_task_status" required><option value="1">Pending</option><option value="2" selected>In Progress</option><option value="3">Completed</option></select></td></tr><tr>
<td><label for="letting_task_notes">Notes:</label></td>
<td><textarea id="letting_task_notes" name="letting_task_notes" rows="6" cols="40"></textarea></td>
</tr></table>

</fieldset><fieldset><legend>Actions</legend>
<table class="nobord"><tr><td><input type="submit" value="Save"></td></tr></table>
  </fieldset></form>

Answer 1

最好为您的 ajax 请求创建一个单独的 php 端点，将表单数据添加到您的数据库中，returns 响应为 [=26] =]（因为这就是你要的）。

问题不在你的 JS 中，而是在你对 AJAX 的实现中。您应该得到响应，然后使用数据更新页面的 dom 或显示成功警报等，具体取决于您想要做什么。

您的 AJAX 端点唯一应该响应的是 JSON 响应，没有别的。

有关如何使用 JSON 响应的详细信息，请参阅堆栈上的此问题，因为您现在根本没有这样做。 Returning JSON from a PHP Script

为什么我的 ajaxForm 的成功函数没有被调用？

Why is the success function of my ajaxForm not being called?

javascript

php

jquery

ajax

ajaxform