#UIBarButtonItem 上的选择器

Question

我正在 Swift 2.2 中开发我的第一个 iOS 应用程序，我遇到了以下问题。在实用程序 class 中，我有以下静态方法，由一些不同的 UIViewController.

调用

static func setNavigationControllerStatusBar(myView: UIViewController, title: String, color: CIColor, style: UIBarStyle) {
    let navigation = myView.navigationController!
    navigation.navigationBar.barStyle = style
    navigation.navigationBar.barTintColor = UIColor(CIColor: color)
    navigation.navigationBar.translucent = false
    navigation.navigationBar.tintColor = UIColor.whiteColor()
    myView.navigationItem.title = title
    
    let menuButton = UIBarButtonItem(image: UIImage(named: "menu"),
                                 style: UIBarButtonItemStyle.Plain ,
                                 target: self, action: #selector("Utils.menuClicked(_:)"))
    
    myView.navigationItem.leftBarButtonItem = menuButton
}

func menuClicked(sender: UIButton!) {
    // do stuff
}

我正在尝试通过一些不同的方式为这个按钮关联一个 #selector，但是我总是遇到以下错误。

Answer 1

没有引号。

#selector(Utils.menuClicked(_:))

func menuClicked 应该在您的视图控制器中 class。但如果由于某种原因不是，你可以做

class Utils {
    static let instance = Utils()

    let menuButton = UIBarButtonItem(image: UIImage(named: "menu"),
                                     style: UIBarButtonItemStyle.Plain ,
                                     target: Utils.instance, action: #selector(Utils.menuClicked(_:)))

    @objc func menuClicked(sender: UIBarButtonItem) {
        // do stuff
    }
}

Answer 2

Swift 2.2 deprecates using strings for selectors and instead introduces new syntax: #selector. Using #selector will check your code at compile time to make sure the method you want to call actually exists. Even better, if the method doesn’t exist, you’ll get a compile error: Xcode will refuse to build your app, thus banishing to oblivion another possible source of bugs.

因此在 #selector 中删除您的方法的双引号。应该有用！

#UIBarButtonItem 上的选择器

#selector on UIBarButtonItem

selector

uibarbuttonitem

ios

swift