合并两个关联数组而不重新索引 - PHP
Merge two associative arrays without reindexing - PHP
如果不重新索引,我如何合并 2 个关联数组?我不想使用 foreach 或 for 循环,有更好的主意吗?
$a1=array(555=>array('name'=>'First Name','surname'=>'Second Name'), 888=>array('name'=>'New First Name','surname'=>'New Second Name'));
$a2=array(888=>array('invite'=>false), 555=>array('invite'=>true));
$result=array(555=>array('name'=>'First Name','surname'=>'Second Name', 'invite'=>true), 888=>array('name'=>'New First Name','surname'=>'New Second Name', 'invite'=>false));
使用array_merge
函数或$a1 + $a2
.
使用array_replace_recursive
将邀请项添加到相应的源数组元素
array_replace_recursive($a1, $a2);
你应该使用array_replace_recursive函数
$a1=array(555=>array('name'=>'First Name','surname'=>'Second Name'), 888=>array('name'=>'New First Name','surname'=>'New Second Name'));
$a2=array(888=>array('invite'=>false), 555=>array('invite'=>true));
print_r(array_replace_recursive($a1, $a2));
这将打印:
Array ( [555] => Array ( [name] => First Name [surname] => Second Name [invite] => 1 ) [888] => Array ( [name] => New First Name [surname] => New Second Name [invite] => ) )
如果不重新索引,我如何合并 2 个关联数组?我不想使用 foreach 或 for 循环,有更好的主意吗?
$a1=array(555=>array('name'=>'First Name','surname'=>'Second Name'), 888=>array('name'=>'New First Name','surname'=>'New Second Name'));
$a2=array(888=>array('invite'=>false), 555=>array('invite'=>true));
$result=array(555=>array('name'=>'First Name','surname'=>'Second Name', 'invite'=>true), 888=>array('name'=>'New First Name','surname'=>'New Second Name', 'invite'=>false));
使用array_merge
函数或$a1 + $a2
.
使用array_replace_recursive
将邀请项添加到相应的源数组元素
array_replace_recursive($a1, $a2);
你应该使用array_replace_recursive函数
$a1=array(555=>array('name'=>'First Name','surname'=>'Second Name'), 888=>array('name'=>'New First Name','surname'=>'New Second Name'));
$a2=array(888=>array('invite'=>false), 555=>array('invite'=>true));
print_r(array_replace_recursive($a1, $a2));
这将打印:
Array ( [555] => Array ( [name] => First Name [surname] => Second Name [invite] => 1 ) [888] => Array ( [name] => New First Name [surname] => New Second Name [invite] => ) )