Apache Hive - 单次插入日期值

Question

我正在尝试使用 Hive 将日期插入日期列。到目前为止，这是我尝试过的

INSERT INTO table1 (EmpNo, DOB)
VALUES ('Clerk#0008000', cast(substring(from_unixtime(unix_timestamp(cast('2016-01-01' as string), 'yyyy-MM-dd')),1,10) as date));

和

INSERT INTO table table1 values('Clerk#0008000', cast(substring(from_unixtime(unix_timestamp(cast('2016-01-01' as string), 'yyyy-MM-dd')),1,10) as date));

和

INSERT INTO table1 SELECT 
'Clerk#0008000', cast(substring(from_unixtime(unix_timestamp(cast('2016-01-01' as string), 'yyyy-MM-dd')),1,10) as date);

但我仍然得到

FAILED: SemanticException [Error 10293]: Unable to create temp file for insert values Expression of type TOK_FUNCTION not supported in insert/values

或

FAILED: ParseException line 2:186 Failed to recognize predicate '<EOF>'. Failed rule: 'regularBody' in statement

Hive ACID 已在基于 table 的 ORC 上启用，没有日期的简单插入工作正常。

我想我错过了一些非常简单的东西。但不能把我的手指放在上面。

Answer 1

好的。我找到了。我现在觉得自己像个傻瓜。

就这么简单

INSERT INTO table1 values ('Clerk#0008000', '2016-01-01');

Apache Hive - 单次插入日期值

Apache Hive - Single Insert Date Value

hadoop

hiveql

apache-hive