Python 中第二个定义的语法错误

Question

def specificChecker(someThing, checker):
    if checker == None:
        return someThing
    elif checker == True:
        return not someThing
    else:
        return None

def whatDoesTheCheckerSay(someThing):
    if specificChecker(someThing) == someThing:
        return 'The checker value was False on that one.'
    elif specificChecker(someThing) == not someThing:
        return 'The checker value was True on that one.'
    elif specificChecker(someThing) == None:
        return 'Something irregular happend. The checker value wasn\'t None or True.'
    else:
        return 'Something went really wrong. This doesn\'t even not work.'

reallySomeThing = input('Type in really some thing: ')
theChecker = input('Set the checker to something: ')

print(specificChecker(reallySomeThing, theChecker))
print(whatDoesTheCheckerSay(reallySomeThing)) # This can be made more efficient, right?

def one(someShit):
    return someShit + ' AWWW YEAH!'

def two(someShit):
    return one(someShit)

print(two(input('Type in some kind of stuff: ')))

我是一个自学成才的初学者，所以这肯定是一些笨拙的基础知识。我正在使用 IDLE shell 并且在我的代码的第二个定义语句中反复出现语法错误。请帮忙？

Answer 1

您不能使用以下行：

elif specificChecker(someThing) == not someThing:

这个一定要写

elif specificChecker(someThing) != someThing:

有效Python.

这也是有效的，但可能不太可读：

elif (specificChecker(someThing)) == (not someThing):

OP编辑后：

新错误是参数（始终为 1）与需要 2 个参数的函数不匹配。您必须将两个参数传递给 specificChecker 而不是一个

Answer 2

第 12 行：elif specificChecker(someThing) == not someThing:

如果你想检查某个变量是否不是某个变量，使用 is not 布尔值或 != 值和字符串

Python 中第二个定义的语法错误

Syntax error at second definition in Python

python

syntax

function

definition