PHP + XPath 获取指定日期之间的节点值

Question

我的 XML 文件看起来像：

<record>
    <name>John</name>
    <StartDate>01-05-2016</StartDate>
    <EndDate>30-10-2016</EndDate>
</record>
<record>
    <name>Jerry</name>
    <StartDate>29-04-2016</StartDate>
    <EndDate>30-06-2016</EndDate>
</record>
<record>
    <name>Mike</name>
    <StartDate>05-06-2016</StartDate>
    <EndDate>25-08-2016</EndDate>
</record>

我有两个约会说:

start date: 30-04-2016 and,
end date: 27-08-2016

我想编写一个 Xpath 查询，它将 return 所有具有 <StartDate> 和 <EndDate> 在上述两个日期（包括两者）之间的记录。

Answer 1

    $startDate = date_format(date_create('30-04-2016'),'d-m-Y');
    $endDate = date_format(date_create('27-08-2016'),'d-m-Y');
    $doc = new DOMDocument();
    $doc->loadXML('<records><record><name>John</name><StartDate>01-05-2016</StartDate><EndDate>30-10-2016</EndDate></record><record><name>Jerry</name><StartDate>29-04-2016</StartDate><EndDate>30-06-2016</EndDate></record><record><name>Mike</name><StartDate>05-06-2016</StartDate><EndDate>25-08-2016</EndDate></record></records>');

    $xpath = new DOMXpath($doc);


    //Get all XML "RECORDS"
    $elements = $xpath->query("//record");
    // Loop through the result elements of the xpath query
    if (!is_null($elements)) {
      foreach ($elements as $element) {
        $nodes = $element->childNodes;
        foreach ($nodes as $node) {
        // Use two logical type variables for each element
        ($node->nodeName=='StartDate' && date_format(date_create($node->nodeValue),'d-m-Y')>=$startDate) ? $stD = 1 : $stD = 0;           
        ($node->nodeName=='EndDate' && date_format(date_create($node->nodeValue),'d-m-Y')<=$endDate) ?  $edD = 1 : $edD = 0;

        }
        // if both $stD and $edD variables do not have logical 1 as value then our $element does not meet the expected dates condition so we remove it from the xml string
        if($stD!=1 && $edD!=1) {
            $element->parentNode->removeChild($element);
        }
      }
      echo $doc->saveXML();    
    }

检查PHP Sandbox

中的上述输出

Answer 2

您可以解析数据并添加到数组中，作为 stdClass 或您最喜欢的任何类型：

<?php

$xml =
    '<root>
        <record>
            <name>John</name>
            <StartDate>01-05-2016</StartDate>
            <EndDate>30-10-2016</EndDate>
        </record>
        <record>
            <name>Jerry</name>
            <StartDate>29-04-2016</StartDate>
            <EndDate>30-06-2016</EndDate>
        </record>
        <record>
            <name>Mike</name>
            <StartDate>05-06-2016</StartDate>
            <EndDate>25-08-2016</EndDate>
        </record>
    </root>';

$doc= new DOMDocument();
$doc->loadXML($xml);
$xpath = new DOMXpath($doc);
$elements = $xpath->query("//record");

$output = [];

$format = 'd-m-Y';
$startDate = DateTime::createFromFormat($format, '30-04-2016');
$endDate = DateTime::createFromFormat($format, '27-08-2016');

foreach($elements as $element) {
    $elementStartDate = DateTime::createFromFormat($format, $element->getElementsByTagName("StartDate")->item(0)->nodeValue);
    $elementEndDate = DateTime::createFromFormat($format, $element->getElementsByTagName("EndDate")->item(0)->nodeValue);

    if( ($startDate <= $elementStartDate) &&
        ($endDate >= $elementEndDate)) {
        $obj = new stdClass;
        $obj->name = $element->getElementsByTagName("name")->item(0)->nodeValue;
        $obj->startDate = $element->getElementsByTagName("StartDate")->item(0)->nodeValue;
        $obj->endDate = $element->getElementsByTagName("EndDate")->item(0)->nodeValue;
        $output[] = $obj;
    }
}

var_dump($output);

输出

array(1) {
  [0]=>
  object(stdClass)#10 (3) {
    ["name"]=>
    string(4) "Mike"
    ["startDate"]=>
    string(10) "05-06-2016"
    ["endDate"]=>
    string(10) "25-08-2016"
  }
}

Answer 3

I have Two Dates Say :
start date: 30-04-2016 and,
end date: 27-08-2016
I want to write a Xpath Query which will return all the record which have <StartDate> and <EndDate> In between the above two dates(Both Inclusive).

这是一个单一的纯 XPath 2.0 表达式，它选择了所有这样的 <record> 元素：

/*/record
[xs:date(string-join(reverse(tokenize(StartDate, '-')), '-')) ge xs:date('2016-04-30') 
and xs:date(string-join(reverse(tokenize(EndDate, '-')), '-')) le xs:date('2016-08-27')]

基于XSLT的验证:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:xs="http://www.w3.org/2001/XMLSchema">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

  <xsl:template match="/">
    <xsl:copy-of select=
    "/*/record
        [xs:date(string-join(reverse(tokenize(StartDate, '-')), '-')) 
         ge xs:date('2016-04-30') 
        and xs:date(string-join(reverse(tokenize(EndDate, '-')), '-')) 
         le xs:date('2016-08-27')]"/>
  </xsl:template>
</xsl:stylesheet>

当此转换应用于以下 XML 文档时（提供的具有顶级元素父元素的片段）：

<t>
    <record>
      <name>John</name>
      <StartDate>01-05-2016</StartDate>
      <EndDate>30-10-2016</EndDate>
    </record>
    <record>
      <name>Jerry</name>
      <StartDate>29-04-2016</StartDate>
      <EndDate>30-06-2016</EndDate>
    </record>
    <record>
      <name>Mike</name>
      <StartDate>05-06-2016</StartDate>
      <EndDate>25-08-2016</EndDate>
   </record>
</t>

计算 Xpath 表达式并将所选节点（在本例中只有一个）复制到输出：

<record>
  <name>Mike</name>
  <StartDate>05-06-2016</StartDate>
  <EndDate>25-08-2016</EndDate>
</record>

二． XPath 1.0 解决方案

等效的 XPath 1.0 表达式是：

/*/record
    [concat(substring(StartDate,7), substring(StartDate,4,2), substring(StartDate,1,2)) 
      >= 20160430
   and not(concat(substring(EndDate,7), substring(EndDate,4,2), substring(EndDate,1,2)) 
           > 20160827)]

基于 XSLT 1.0 的验证:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

  <xsl:template match="/">
    <xsl:copy-of select=
    "/*/record
        [concat(substring(StartDate,7), substring(StartDate,4,2), substring(StartDate,1,2)) 
          >= 20160430
       and not(concat(substring(EndDate,7), substring(EndDate,4,2), substring(EndDate,1,2)) 
                > 20160827)]"/>
  </xsl:template>
</xsl:stylesheet>

当此转换应用于与上面相同的 XML 文档时，会产生相同的、正确的结果:

<record>
   <name>Mike</name>
   <StartDate>05-06-2016</StartDate>
   <EndDate>25-08-2016</EndDate>
</record>

PHP + XPath 获取指定日期之间的节点值

PHP + XPath get nodes value in between Specified Dates

php

xml

xpath

xpath-2.0