两个日期之间按小时分组经过了多少秒

Question

假设我有一个开始日期 2016-06-19 09:30:00 和一个结束日期 2016-06-19 10:20:00

我想得到在下一个小时开始之前或到达最后时间之前每小时经过的时间（以秒为单位按小时和日期分组），这是我想要达到的结果（没有任何成功）会是这样的：

hour |    date    | time_elapsed_in_seconds
 9   | 2016-06-19 |  1800 (there are 1800 seconds between 09:30:00 and 10:00:00)
 10  | 2016-06-19 |  1200 (there are 1200 seconds between 10:00:00 and 10:20:00)

Answer 1

试试这个：

        with table1 as (
      select '2016-06-19 09:30:00'::timestamp without time zone start_date,'2016-06-19 10:20:00'::timestamp without time zone end_date
      )


    select extract(hour from the_hour) "hour",the_hour::date "date",extract (epoch from (new_end-new_start)) "time_elapsed" from (
        select the_hour,CASE WHEN date_trunc('hour',start_date)=the_hour then start_date else the_hour end new_start,
                    CASE WHEN date_trunc('hour',end_date)=the_hour then end_date else the_hour+'1 hour'::interval end new_end 
           from (
              select generate_series(date_trunc('hour',start_date),end_date,'1 hour'::interval) the_hour,start_date,end_date from table1 
            ) a 
         ) b

两个日期之间按小时分组经过了多少秒

How many seconds passed by grouped by hour between two dates

postgresql

date-arithmetic

seconds