在 R 中组合两个具有不同行数的数据框

Combine two data frames with different number of rows in R

我有两个数据框,link 和 body:

link是这样的:

wpt        ID
1          1235
mediate    4562
mediate    0928
2          6351
3          3826
mediate    0835

body是这样的:

wpt   fuel    distance
1     2221    53927
2     4821    48261
3     8362    47151

我期望的输出是这样的:

wpt      fuel   distance   ID
1        2221   53927      1235
mediate  NA     NA         4562
mediate  NA     NA         0928
2        4821   48261      6351
3        8362   47151      3826
mediate  NA     NA         0835

我试过使用"merge"函数,没成功。假设使用 "mediate" 的行号作为索引来拆分 "body" 并逐个 rbind 它们可能会起作用。有更好的方法吗?看到有人可以帮忙吗?

提前致谢!

df1 <- data.frame(wpt = c(1, "meditate", "meditate", 2,3,"meditate"), 
              ID = c(1235, 4562, 0928,6351,3826,0835))
df1$wpt <- as.character(df1$wpt)


df2 <- data.frame(wpt = c(1,2,3), 
              fuel = c(1235, 4562, 0928), 
              distance = c(2,3,4))
df2$wpt <- as.character(df2$wpt)


library(dplyr)
full_join(df1, df2, by = "wpt")

不要介意数值!您可以随时重新排列列。

       wpt   ID fuel distance
1        1 1235 1235        2
2 meditate 4562   NA       NA
3 meditate  928   NA       NA
4        2 6351 4562        3
5        3 3826  928        4
6 meditate  835   NA       NA

我们可以使用left_join

library(dplyr)
mutate(df2, wpt = as.character(wpt)) %>% 
                  left_join(df1, ., by = 'wpt')
#      wpt   ID fuel distance
#1       1 1235 2221    53927
#2 mediate 4562   NA       NA
#3 mediate  928   NA       NA
#4       2 6351 4821    48261
#5       3 3826 8362    47151
#6 mediate  835   NA       NA

或使用data.table

library(data.table)
setDT(df2)[, wpt := as.character(wpt)][df1, on = "wpt"]
#       wpt fuel distance   ID
#1:       1 2221    53927 1235
#2: mediate   NA       NA 4562
#3: mediate   NA       NA  928
#4:       2 4821    48261 6351
#5:       3 8362    47151 3826
#6: mediate   NA       NA  835

我认为以下应该可行:

library(data.table)
setkey(link,wpt)
setkey(body,wpt)
merge(link,body,by="wpt",all.x=T)

这是围绕 match() 构建的非合并基础 R 解决方案:

link[names(body)[-1L]] <- body[match(link[,1L],body[,1L]),-1L];
link;
##       wpt   ID fuel distance
## 1       1 1235 2221    53927
## 2 mediate 4562   NA       NA
## 3 mediate 0928   NA       NA
## 4       2 6351 4821    48261
## 5       3 3826 8362    47151
## 6 mediate 0835   NA       NA

数据

link <- data.frame(wpt=c('1','mediate','mediate','2','3','mediate'),ID=c('1235','4562','0928'
,'6351','3826','0835'),stringsAsFactors=F);
body <- data.frame(wpt=c(1L,2L,3L),fuel=c(2221L,4821L,8362L),distance=c(53927L,48261L,47151L)
);