如何检查日期在两个给定日期之间

How to check date day is between two given days

我必须检查我的特定日期是否在两个字符串日期之间或等于它们 例如:

var startDay = "Saturday";
var endDay = "Tuesday";
DateTime myDate = DateTime.Now;
if(myDate.DayofWeek >= startDay && myDate.DayofWeek <= endDay){
//some code here...
}

您可以使用 DayOfWeek 枚举。

if(myDate.DayOfWeek >= DayOfWeek.Tuesday 
   && myDate.DayOfWeek <= DayOfWeek.Saturday)
{
    // This would catch the days from Tuesday to Saturday
}

如果你想赶上从星期六到星期二的日子,你必须稍微更改一下你的代码。

    if(myDate.DayOfWeek >= DayOfWeek.Saturday 
    || myDate.DayOfWeek <= DayOfWeek.Tuesday)
{
    // This would catch the days from Tuesday to Saturday
}

如果您的 startDateendDate 正在更改。然后你需要解析第一个并做一些额外的检查。

DayOfWeek startDayOfWeek;
DayOfWeek endDayOfWeek;
if (!Enum.TryParse(startDay, out startDayOfWeek))
{
    // Something wrong happened and you have to handle it.
}
if (!Enum.TryParse(endDay, out endDayOfWeek))
{
    // Something wrong happened and you have to handle it.
}
if (
       ((int)startDayOfWeek < (int)endDayOfWeek
         && myDate.DayOfWeek >= startDayOfWeek
         && myDate.DayOfWeek <= endDayOfWeek)
    || ((int)startDayOfWeek > (int)endDayOfWeek
         && (myDate.DayOfWeek >= startDayOfWeek
             || myDate.DayOfWeek <= endDayOfWeek))
   )
{

}

您可以将这些字符串解析为 DayOfWeek 枚举:

var startDay = "Saturday";
var endDay = "Tuesday";
DayOfWeek startDayOfWeek, endDayOfWeek;
if (!Enum.TryParse(startDay, out startDayOfWeek))
   // error handlnig
if (!Enum.TryParse(endDay, out endDayOfWeek))
   // error handlnig
DateTime myDate = DateTime.Now;
if(myDate.DayofWeek >= startDayOfWeek && myDate.DayofWeek <= endDayOfWeek){
    //some code here...
}

但这会带来另一个问题:DayOfWeek 的值从星期日 (0) 到星期六 (6)。根据您定义的一周开始时间或 between 的含义,您可能需要调整这些值。

所以这里有一个建议:

int startDayAsInt = (int)startDayOfWeek; // the parsed value from above
int endDayAsInt = (int)endDayOfWeek;
int myDateAsInt = (int)myDate.DayOfWeek;

if (endDayAsInt < startDayAsInt) endDayAsInt += 7;
if (myDateAsInt < startDayAsInt) myDateAsInt += 7;
if (myDateAsInt >= startDayAsInt && myDateAsInt <= endDayAsInt)
    // do something

这应该适用于所有组合,因为它会将 "next" 周的天数投射到开始日之前。