如何将字符串解析为字符串类型的不同arraylist

Question

我有一个字符串，其中包含 4 个东西，我想将每个东西都存储在一个列表中。该字符串包含从 android 到服务器的食品订单，在服务器中我必须解析它才能显示。字符串看起来像：

[:ordername:ordertime:orderprice: orderquantity:]

对于 1 个订单案例，我想在名称列表中输入订单名称，在时间列表中输入订单时间，在价目表中输入订单价格等如果超过 1 个订单，它将用逗号分隔，如

[:ordername:ordertime:orderprice:orderquantity:],[:ordername2:ordertime2:orderprice2:orderquantity2:]

我想在名单中输入 ordername,ordername2 并在时间列表中输入 ordertime, ordertime2 以及 orderprice , orderprice2在价目表等。

这是我试过的

String orderlist=request.getParameter("orderlist"); // this is a string which is coming from android to server containing orders

char[] orderarray=orderlist.toCharArray(); //converting string to char array
int comma_counter = 0;
int comma_counter1 = 0;

for (int i=0; i < orderlist.length(); i++){
    if (orderarray[i]==','){
    comma_counter++;
}

}
      System.out.println("counter is"+comma_counter);
      System.out.println("order list length"+orderlist.length());


ArrayList <String> order_array_list = new ArrayList <String>();

int no=0;

String temp="";

    for (int j=no; j<orderarray.length; j++){
    System.out.println(" j is "+ j); 


        if(orderarray[j]!=','){
            temp = temp+orderarray[j];
           // System.out.println("temp is "+temp);

        }
        else if(orderarray[j]==','){
        order_array_list.add(temp); 
        temp="";
           no=j;
        }
      }
    String []parts= null;
    for(int i=0; i<order_array_list.size(); i++){
        String array= order_array_list.get(i);

        parts= array.split(":");

        for(int j=0; j<parts.length; j++)
        {
            System.out.println(parts[j]);
        }

    }

Answer 1

像这样的东西会起作用：

Map <Integer, List <String>> map = new HashMap <>();

// Initialize the map
map.put(1, new ArrayList <String> ());
map.put(2, new ArrayList <String> ());
map.put(3, new ArrayList <String> ());
map.put(4, new ArrayList <String> ());

String str = "[:ordername:ordertime:orderprice:orderquantity:]," + 
             "[:ordername2:ordertime2:orderprice2:orderquantity2:]";

// loop through each order set
for (String s: str.split(","))
{
    // remove any leading and trailing spaces
    s = s.trim();

    // remove the brackets 
    s = s.replaceAll("[\[\]]", "");

    int i = 1;

    // loop through each order component
    for (String c: s.split(":"))
    {
        // remove any leading and trailing spaces
        c = c.trim();
        if (c.length() > 0)
        {
            map.get(i).add(c);
            i++;
        }
    }
}

System.out.println(map);

输出：

{1=[ordername, ordername2], 2=[ordertime, ordertime2], 3=[orderprice, orderprice2], 4=[orderquantity, orderquantity2]}

注意：为简单起见，我使用 HashMap 来包含所有列表，但您可以在 [=11= 之外创建 4 个列表] 如果你希望。在这种情况下，您需要在 if (c.length() > 0) 语句中包含 if/else if 条件。

Answer 2

希望此代码对您有所帮助

      import java.util.ArrayList;
      import java.util.List;

       public class MainClass {
public static void main(String[] args) {
   String input = "[:ordername:ordertime:orderprice:orderquantity:],                            [:ordername2:ordertime2:orderprice2:orderquantity2:]";

input = input.replace("[:", "");
input = input.replace(":]", "");

String[] inputArray = input.split(",");

List<String> nameList = new ArrayList<String>();
List<String> timeList = new ArrayList<String>();
List<String> priceList = new ArrayList<String>();
List<String> quantityList = new ArrayList<String>();

for (String order : inputArray) {
  String[] orderDetails = order.split(":");
  nameList.add(orderDetails[0]);
  timeList.add(orderDetails[1]);
  priceList.add(orderDetails[2]);
  quantityList.add(orderDetails[3]);
}
    }
    }

如果您更关心性能，您可以使用 apache commons 来替换字符串。

如何将字符串解析为字符串类型的不同arraylist

How to parse the string in to different arraylist of string type

java

arraylist

string-parsing