C++ 将无符号转换为有符号

Question

我尝试复制 this 但无法编译。

unsigned char x = 0;
reinterpret_cast<signed char>(x);

它说

C:\Users\SXG5558\Documents\Arduino\sketch_jun30a\sketch_jun30a.ino: In function 'void setup()':

sketch_jun30a:3: error: invalid cast from type 'unsigned char' to type 'signed char'

     reinterpret_cast<signed char>(x);

                                    ^

exit status 1

编辑：

明确地说，我真的很想将内存中的位从有符号重新解释为无符号。我正在编写一个读取和写入未签名数据的 I2C 库，但我正在使用该库来控制已签名的传感器，因此我想重新解释转换实际数据。

Answer 1

cppreference.com 中的相关部分是

Type aliasing

When a pointer or reference to object whose dynamic type is DynamicType is reinterpret_cast (or C-style cast) to a pointer or reference to object of a different type AliasedType, the cast always succeeds, but the resulting pointer or reference may only be used to access the object if one of the following is true:

[...]

AliasedType is the (possibly cv-qualified) signed or unsigned variant of DynamicType

[...]

即。您忘记了链接示例中的 &。

C++ 将无符号转换为有符号

C++ cast unsigned to signed

c++

arduino

reinterpret-cast