函数定义后装饰?
Decorate a function after it is defined?
我认为答案是否定的,但我似乎找不到明确的说法。我有以下情况;
def decorated_function(function):
@functools.wraps(function)
def my_function():
print "Hello %s" % function.__name__
return my_function
for attr, value in dct.iteritems():
dct[attr] = decorated_function(value)
而我真正想要的是这样的东西;
def my_function(function):
print "Hello %s" % function.__name__
for attr, value in dct.iteritems():
dct[attr] = functools.wraps(my_function, value)
删除 decorated_function 令人困惑的 shell。装饰器只能在定义函数时应用吗?
您可以在定义函数后对其进行修饰。事实上,函数装饰器只是语法糖。例如,您可以替换
@classmethod
@synchronized(lock)
def foo(cls):
pass
与
def foo(cls):
pass
foo = synchronized(lock)(foo)
foo = classmethod(foo)
我认为答案是否定的,但我似乎找不到明确的说法。我有以下情况;
def decorated_function(function):
@functools.wraps(function)
def my_function():
print "Hello %s" % function.__name__
return my_function
for attr, value in dct.iteritems():
dct[attr] = decorated_function(value)
而我真正想要的是这样的东西;
def my_function(function):
print "Hello %s" % function.__name__
for attr, value in dct.iteritems():
dct[attr] = functools.wraps(my_function, value)
删除 decorated_function 令人困惑的 shell。装饰器只能在定义函数时应用吗?
您可以在定义函数后对其进行修饰。事实上,函数装饰器只是语法糖。例如,您可以替换
@classmethod
@synchronized(lock)
def foo(cls):
pass
与
def foo(cls):
pass
foo = synchronized(lock)(foo)
foo = classmethod(foo)