Java 持续时间的最大值是多少
What is the Maximum value for Java Duration
我尝试使用 Duration.ofMillis(Long.MAX_VALUE) 在 Java 8 中创建最大持续时间，但出现了长时间溢出。
如果 Duration.MAX_VALUE 存在，我将如何以编程方式获得它的等价物？
编辑：长溢出很可能是由于尝试添加到值而不是在构造期间引起的。抱歉没有可重现的代码。
根据 Javadoc:
The duration uses nanosecond resolution with a maximum value of the seconds that can be held in a long.
The range of a duration requires the storage of a number larger than a long. To achieve this, the class stores a long representing seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The model is of a directed duration, meaning that the duration may be negative.
看起来 Duration 以秒（最多 Long.MAX_VALUE）和纳秒（最多 999,999,999）存储。那么可能的最大持续时间是：
Duration d = Duration.ofSeconds(Long.MAX_VALUE, 999_999_999);
当我打印它时 (System.out.print(d)) 我得到以下信息：
PT2562047788015215H30M7.999999999S
这意味着：2562047788015215 小时 30 分钟 7.999999999 秒。
简单：
Duration maxDur = ChronoUnit.FOREVER.getDuration();
我尝试使用 Duration.ofMillis(Long.MAX_VALUE) 在 Java 8 中创建最大持续时间，但出现了长时间溢出。 如果 Duration.MAX_VALUE 存在，我将如何以编程方式获得它的等价物？
编辑：长溢出很可能是由于尝试添加到值而不是在构造期间引起的。抱歉没有可重现的代码。
根据 Javadoc:
The duration uses nanosecond resolution with a maximum value of the seconds that can be held in a long.
The range of a duration requires the storage of a number larger than a long. To achieve this, the class stores a long representing seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The model is of a directed duration, meaning that the duration may be negative.
看起来 Duration 以秒（最多 Long.MAX_VALUE）和纳秒（最多 999,999,999）存储。那么可能的最大持续时间是：
Duration d = Duration.ofSeconds(Long.MAX_VALUE, 999_999_999);
当我打印它时 (System.out.print(d)) 我得到以下信息：
PT2562047788015215H30M7.999999999S
这意味着：2562047788015215 小时 30 分钟 7.999999999 秒。
简单：
Duration maxDur = ChronoUnit.FOREVER.getDuration();