特定键的字典的总和值 C#

Question

我有一个字典，其中有两个相似的键，一个拼写错误，因此它创建了另一个键，我想对它的值求和，然后删除拼写错误的 key/value 对。

如果我有一个部门字典，以部门名称为键，该部门的人员数量为值，我想将 "Marketing" 和 [=21 的值相加=] 并删除拼写错误的 key/value 对 "Marketin"。

        var departments = new Dictionary<string, int>()
        {
            { "HR", 33 },
            { "Management", 8 },
            { "Marketing", 21 },
            { "Marketin", 4 },
            { "Sales", 44 }
        };

我希望字典看起来像这样：

        var departments = new Dictionary<string, int>()
        {
            { "HR", 33 },
            { "Management", 8 },
            { "Marketing", 25 },
            { "Sales", 44 }
        };

字典已经创建，所以我只是为了说明目的使用了初始化。

Answer 1

departments["Marketing"] += departments["Marketin"];

departments.Remove("Marketin");

Answer 2

这是一个代码示例，它说明了您可以用来执行所需操作的词典功能。

至于您需要使用这些功能的哪种组合来实现您的确切目的，我将把它作为练习留给您。如果您需要更多帮助。发表评论，准确解释您不理解的内容。

//how to get a value in your dictionary
string myValue = departments["Marketin"];

//how to update a value in your dictionary
departments["Marketing"] = 5;

//how to remove a value in your dictionary
departments.Remove("Marketin");

//how to iterate over your dictionary
foreach(var department in departments)
{
    //only print the value if it's "Marketin"
    if(department.Key == "Marketin")
    {
        Console.WriteLine(department.Value);
    }
}

Answer 3

I would like to sum the values for "Marketing" and "Marketin" and delete the misspelled key/value pair "Marketin".

这里是用户识别出问题文本和正确文本，然后删除不正确的文本并将值添加（求和）到正确键的值。

var departments = new Dictionary<string, int>()
{
    { "HR", 33 },
    { "Management", 8 },
    { "Marketing", 21 },
    { "Marketin", 4 },
    { "Sales", 44 }
};

var baseText  = "Market";
var validText = "Marketing";

var removal = departments.ToList()
                         .Where(itm => itm.Key.StartsWith(baseText) && 
                                       itm.Key.Equals(validText) == false)
                         .ToList();   

removal.ForEach(itm => departments.Remove(itm.Key));

departments[validText] += removal.Sum(itm => itm.Value);

最终结果：

Answer 4

这是我对更多 "generic" 方法的草图：

var normalisedDepartments = 
   departments.GroupBy(x => Normalise(x.Key), y => y.Value)
             .ToDictionary(x => x.Key, y => y.Sum());

    private static string Normalise(string key)
    {
        if (key == "Marketin")
        {
            return "Marketing";
        }
        return key;
    }

然后你可以调整 Normalize 方法，以便它识别其他格式错误的键，如果有更多的话。

特定键的字典的总和值 C#

Sum values of a Dictionary for specific keys C#

c#

linq

dictionary

generic-collections