如何获取最小值和最新日期[Sql Server 2008]

Question

我可以获取最新日期，但无法获取最小值。我想在这里得到的是我想为每个患者显示每个 findingAbbr 的最小值，以及该最小值的最新创建日期和时间。有人可以告诉我我在这个查询中做错了什么吗？

感谢您的帮助！！！

WITH cteRankedData As
(
    SELECT DISTINCT
        a.AccountID
         ,e.FindingAbbr
         ,min(e.Value) as Value
         ,e.CreationTime
        ,ROW_NUMBER() OVER (PARTITION BY a.AccountID, e.FindingAbbr ORDER BY e.CreationTime DESC) As RN

FROM      dbo.PatientVisitInfo a with (nolock)
JOIN      dbo.Assessment d with (nolock) ON a.PatientVisit_oid = d.PatientVisit_oid
JOIN      dbo.Observation e with (nolock) ON e.AssessmentID = d.AssessmentID
WHERE
         a.VisitTypeCode='IP'
     AND a.VisitEndDateTime is null
     AND e.Value <> ''
     AND e.FindingAbbr IN ('A_PEEPSet','A_KR_RT_FI02%','A_FIO2%Set','A_FIO2%', 'A_Vent Mode')
     AND e.CreationTime >= DATEADD(d,-1, GETDATE())
     group by a.AccountID ,e.FindingAbbr, e.CreationTime)
SELECT
         AccountID
         ,FindingAbbr
         ,Value
         ,CreationTime


FROM
    cteRankedData
WHERE
    RN = 1

ORDER BY
    AccountID
  ,CreationTime
;

我得到的结果：

AccountID   FindingAbbr Value   CreationTime
1           _FIO2%        40   1/7/15 1:55 PM
2           A_FIO2%       60   1/7/15 8:20 AM
2           A_FIO2%Set    60   1/7/15 9:47 AM
2           A_PEEPSet     8    1/7/15 9:47 AM
2           A_Vent Mode   CMV  1/7/15 9:47 AM
3           A_FIO2%Set    70   1/7/15 7:21 AM
4           A_KR_RT_FI02% 30   1/6/15 2:54 PM
4           A_FIO2%       30   1/7/15 9:35 AM
4           A_FIO2%Set    45   1/7/15 10:22 AM
4           A_PEEPSet     5    1/7/15 10:22 AM
4           A_Vent Mode   CMV  1/7/15 10:22 AM

所有结果：

AccountID   FindingAbbr Value   CreationTime
1           A_FIO2%       40   1/7/15 1:55 PM
2           A_FIO2%       60   1/7/15 8:20 AM
2           A_FIO2%       60   1/7/15 8:20 AM
2           A_FIO2%       100  1/7/15 1:31 AM
2           A_FIO2%       100  1/7/15 3:30 AM
2           A_FIO2%   Other:70 1/7/15 4:11 AM
2           A_FIO2%Set    60   1/7/15 3:49 AM
2           A_FIO2%Set    60   1/7/15 9:45 AM
2           A_FIO2%Set    60   1/7/15 9:47 AM
2           A_FIO2%Set    100  1/7/15 1:29 AM
2           A_PEEPSet     8    1/7/15 1:29 AM
2           A_PEEPSet     8    1/7/15 9:47 AM
2           A_PEEPSet     5    1/7/15 9:45 AM
2           A_PEEPSet     8    1/7/15 3:49 AM
2           A_Vent Mode   CMV  1/7/15 3:49 AM
2           A_Vent Mode   CMV  1/7/15 9:45 AM
2           A_Vent Mode   CMV  1/7/15 9:47 AM
2           A_Vent Mode   CMV  1/7/15 1:29 AM
3           A_FIO2%Set    70   1/6/15 3:09 PM
3           A_FIO2%Set    70   1/7/15 7:21 AM
4           A_FIO2%       30   1/7/15 4:26 AM
4           A_FIO2%       30   1/7/15 9:35 AM
4           A_FIO2%Set    45   1/7/15 9:53 AM
4           A_FIO2%Set    45   1/7/15 10:22 AM
4           A_FIO2%Set    45   1/7/15 3:55 AM
4           A_FIO2%Set    45   1/6/15 7:22 PM
4           A_FIO2%Set    45   1/6/15 11:02 PM
4           A_KR_RT_FI02% 30   1/6/15 2:54 PM
4           A_PEEPSet     5    1/6/15 7:22 PM
4           A_PEEPSet     5    1/6/15 11:02 PM
4           A_PEEPSet     5    1/7/15 3:55 AM
4           A_PEEPSet     5    1/7/15 10:22 AM
4           A_PEEPSet     5    1/7/15 9:53 AM
4           A_Vent Mode   CMV  1/7/15 9:53 AM
4           A_Vent Mode   CMV  1/7/15 10:22 AM
4           A_Vent Mode   CMV  1/7/15 3:55 AM
4           A_Vent Mode   CMV  1/6/15 11:02 PM
4           A_Vent Mode   CMV  1/6/15 7:22 PM
4           A_Vent Mode   CPAP 1/6/15 2:54 PM

我想要的结果：

AccountID   FindingAbbr  Value   CreationTime
1           A_FIO2%       40   1/7/15 1:55 PM
2           A_FIO2%       60   1/7/15 8:20 AM
2           A_FIO2%Set    60   1/7/15 9:47 AM
2           A_PEEPSet     5    1/7/15 9:45 AM
2           A_Vent Mode   CMV  1/7/15 9:47 AM
3           A_FIO2%Set    70   1/7/15 7:21 AM
4           A_KR_RT_FI02% 30   1/6/15 2:54 PM
4           A_FIO2%       30   1/7/15 9:35 AM
4           A_FIO2%Set    45   1/7/15 10:22 AM
4           A_PEEPSet     5    1/7/15 10:22 AM
4           A_Vent Mode   CMV  1/7/15 10:22 AM

Answer 1

为什么不将您的最小值和最大创建时间分开，为什么不在您的 ROW_NUMBER() 窗口函数中将它们结合起来

    ROW_NUMBER() OVER (PARTITION BY a.AccountID, e.FindingAbbr 
ORDER BY e.Value, e.CreationTime DESC)

ROW_NUMBER() 1 将是该特定 accountID 和 FindingAbbr 的最低值的最新创建时间。

Answer 2

你很接近。删除 cte 中 Value 列上的 min，将 e.Value 添加到 group by，并将 value 添加到您的 row_number order by RN 列。这应该为您提供每个 findingAbbr 的最小值，以及最近的日期。

WITH cteRankedData As
(
    SELECT DISTINCT
        a.AccountID
         ,e.FindingAbbr
         ,e.Value as Value
         ,e.CreationTime
        ,ROW_NUMBER() OVER (PARTITION BY a.AccountID, e.FindingAbbr ORDER BY e.Value ASC, e.CreationTime DESC) As RN
    FROM      dbo.PatientVisitInfo a with (nolock)
    JOIN      dbo.Assessment d with (nolock) ON a.PatientVisit_oid = d.PatientVisit_oid
    JOIN      dbo.Observation e with (nolock) ON e.AssessmentID = d.AssessmentID
    WHERE
            a.VisitTypeCode='IP'
        AND a.VisitEndDateTime is null
        AND e.Value <> ''
        AND e.FindingAbbr IN ('A_PEEPSet','A_KR_RT_FI02%','A_FIO2%Set','A_FIO2%', 'A_Vent Mode')
        AND e.CreationTime >= DATEADD(d,-1, GETDATE())
    GROUP BY a.AccountID ,e.FindingAbbr, e.CreationTime, e.Value
)
SELECT
     AccountID
    ,FindingAbbr
    ,Value
    ,CreationTime
FROM
    cteRankedData
WHERE
    RN = 1
ORDER BY
    AccountID
  ,CreationTime
;

如何获取最小值和最新日期[Sql Server 2008]

How to get MIN value and latest date [Sql Server 2008]

sql

sql-server-2008