如果一个数字可以被两个数字逻辑C#整除

Question

我想知道如果一个数字可以被两个数字整除，代码会是什么样子。例 15 既能被 3 又能被 5 整除

那我就可以说

Console.WriteLine("This Number is Divisible by 3 and 5!");

我该如何编写代码以及将它放在哪里？请帮忙

using System;

namespace ConsoleApp
{
    class Program
    {
        static void Main(string[] args)
        {
            int n;
            Console.WriteLine("Enter A Number :");
            n = int.Parse(Console.ReadLine());
            if (n % 3 == 0)

            {
                Console.WriteLine("This Number is Divisible by 3 ");

            }

            else
            {
                Console.WriteLine("This Number is Not Divisible by 3");

            }
            Console.ReadLine();

        }
    }
}

Answer 1

using System;

namespace ConsoleApp
{
    class Program
    {
        static void Main(string[] args)
        {
            int n;
            Console.WriteLine("Enter A Number :");
            n = int.Parse(Console.ReadLine());
            if (n % 3 == 0)
            {
                if (n % 5 == 0)
                {
                    Console.WriteLine("This Number is Divisible by 3 and 5!");

                }
                else
                {
                    printf("\nThe number is divisible by 3 but not by 5");
                }
            }

            else if (n % 5 == 0)
            {
                Console.WriteLine("The number is divisible by 5 but not by 3");
            }
            else
            {
                Console.WriteLine("\nThis Number is Not Divisible by 3 and 5!");
            }
            Console.ReadLine();
        }
    }
}

输出：

输入一个数字：21

数字可以被 3 整除但不能被 5 整除

Answer 2

这里有简单的解决方法：

using System;

namespace ConsoleApp
{
class Program
{
    static void Main(string[] args)
    {
        int n;
        Console.WriteLine("Enter A Number :");
        n = int.Parse(Console.ReadLine());
        if (n % 3 == 0 && n % 5 == 0)

        {
            Console.WriteLine("This Number is Divisible by 3 and 5 ");

        }

        else
        {
            Console.WriteLine("This Number is Not Divisible by 3 and 5");

        }
        Console.ReadLine();

    }
}
}

Answer 3

我有一个简单的逻辑给你，它将打印所有因素。通过利用 int.TryParse 的优势来验证输入（如果输入不是数字或不可转换为整数，那么它将显示无效输入消息）。然后它将遍历数字直到给定数字的一半并收集那些可整除的数字。

考虑下面的代码：

int numberInput;
List<int> factors = new List<int>();
Console.WriteLine("Enter A Number :");
if (int.TryParse(Console.ReadLine(), out numberInput))
{
    for (int i = 2; i <= numberInput/2; i++)
    {
        if (numberInput % i == 0)
        {
            factors.Add(i);
        }
    }
    if (factors.Count > 0)
    {
        Console.WriteLine("{0} is divisible by {1}", numberInput, String.Join(",",factors));
    }
    else 
    {
        Console.WriteLine("Number is Prime");
    }

}
else
{
    Console.WriteLine("Wrong Input");
}
Console.ReadKey();

这将输出为

"15 is divisible by 3,5" for an input 15

"20 is divisible by 2,4,5,10" for an input 20

Answer 4

试试这个

    int n, c;
    c = 0;
        Console.WriteLine("Enter A Number :");
        n = int.Parse(Console.ReadLine());
        for (int i = 2; i < n; i++)
    { 
    if (n%i==0)
    {
        c++;
        if(c==1)
        {
        Console.WriteLine("This Number is Divisible by "+i);
        }
        else
        {
        Console.Write(" and "+i);
        }               
    }
      }

如果一个数字可以被两个数字逻辑C#整除

If a num is divisible by two number logic C#

c#

mono

xamarin