sql 将行转为列
sql to transpose rows to columns
我有一个 Oracle 视图(从多个表连接),就像第一个屏幕截图一样。 address_type 应该始终是所有者或 属性。我想得到像第二个屏幕截图那样的结果。如何使用 SQL 来做到这一点?抱歉,我是 SQL.
的初学者
您可以使用内部联接:
select tab1.address_id, tab1.address as owner_address,
tab1.city as owner_city, tab1.state as owner_state,
tab1.zip as owner_zip, tab2.address as property_address,
tab2.city as property_city, tab2.state as property_state,
tab2.zip as property_zip
from tab1
full outer join tab2
on tab1.address_id = tab2.address_id
where tab1.address_type = 'owner'
and tab2.address_type = 'property'
tab1 包含所有 owner 信息,tab2 包含所有 属性 信息。您可以使用 address_id.
加入他们
抱歉我无法测试!
我有一个 Oracle 视图(从多个表连接),就像第一个屏幕截图一样。 address_type 应该始终是所有者或 属性。我想得到像第二个屏幕截图那样的结果。如何使用 SQL 来做到这一点?抱歉,我是 SQL.
的初学者您可以使用内部联接:
select tab1.address_id, tab1.address as owner_address,
tab1.city as owner_city, tab1.state as owner_state,
tab1.zip as owner_zip, tab2.address as property_address,
tab2.city as property_city, tab2.state as property_state,
tab2.zip as property_zip
from tab1
full outer join tab2
on tab1.address_id = tab2.address_id
where tab1.address_type = 'owner'
and tab2.address_type = 'property'
tab1 包含所有 owner 信息,tab2 包含所有 属性 信息。您可以使用 address_id.
加入他们抱歉我无法测试!