如何从 android 中的画廊获取地址

Question

我写了这段代码，我的代码从图库中选择一张图片并从中获取数据，但我不知道如何从 Inputstrem 或数据中获取图像地址并存储它？

public void loadPic()
{
    Intent photoPickerIntent = new Intent(Intent.ACTION_PICK);
    photoPickerIntent.setType("image/*");
    startActivityForResult(photoPickerIntent, 1);
}

    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    if(requestCode==1)
    {
        try {
            Uri selectedImage=data.getData();
            InputStream inputStream = getContentResolver().openInputStream(selectedImage);
            listItems.add(inputStream.toString());
        } catch (FileNotFoundException e) {

            e.printStackTrace();
        }
    }
}

Answer 1

我不确定这是否正是你想要的，但你可以得到这样的图像：

Uri selectedImage = data.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(getActivity().getContentResolver(), selectedImage);

获得位图后，您可以查看here如何存储它。

编辑：试试这个

        Uri selectedImage = data.getData();
        String[] filePathColumn = { MediaStore.Images.Media.DATA };
        Cursor cursor = getContentResolver().query(selectedImage,filePathColumn, null, null, null);
        cursor.moveToFirst();
        int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
        String picturePath = cursor.getString(columnIndex);
        cursor.close();
        ImageView imageView = (ImageView) findViewById(R.id.imgView);
        imageView.setImageBitmap(BitmapFactory.decodeFile(picturePath));

摘自 here.

Answer 2

有时，您无法从您选择的图片中获取文件。这是因为选择的那个来自 Google+、Drive、Dropbox 或任何其他提供商。

最好的解决方案是让系统通过 Intent.ACTION_GET_CONTENT 选择内容，然后通过内容提供商获取结果。

public void pickImage() {
  Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
  intent.setType("image/*");
  startActivityForResult(intent, PICK_PHOTO_FOR_AVATAR);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO_FOR_AVATAR && resultCode == Activity.RESULT_OK) {
        if (data == null) {
            //Display an error
            return;
        }
        InputStream inputStream = context.getContentResolver().openInputStream(data.getData());
        //Now you can do whatever you want with your inpustream, save it as file, upload to a server, decode a bitmap...
    }
}

Answer 3

读取如下文件名，相应地使用它。

            Uri selectedImage = data.getData();
            String[] filePathColumn = { MediaStore.Images.Media.DATA };
            Cursor cursor = getContentResolver().query(selectedImage,
                    filePathColumn, null, null, null);
            cursor.moveToFirst();
            int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
            String picturePath = cursor.getString(columnIndex);
            File f = new File(picturePath);
            String imageName = f.getName();

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