Python 相当于 MySQL "Left Join" 两个元组列表

Question

这似乎很重要（尽管我确实来自 MySQL 背景）。

a = [(1,f,e),(7,r,None),(2,s,f),(32,None,q)]
b = [(32,dd), (1,pp)]

如果我在 MySQL 中执行此操作（LEFT JOIN）：

SELECT a.*, b.* FROM a LEFT JOIN b ON a[0] = b[0]

我得到：

[(1,f,e,1,pp),(7,r,None,None,None),(2,s,f,None,None),(32,None,q,32,dd)]

如何用 python 实现这一点？

（也许我没有在寻找合适的术语...但我不（认为）我想追加、合并或连接...）

Answer 1

你可以通过从第二个输入列表中创建一个字典然后查找它来解决它：

>>> a = [(1,'f','e'),(7,'r',None),(2,'s','f'),(32,None,'q')]
>>> b = [(32,'dd'), (1,'pp')]
>>>
>>> b_dict = {item[0]: item for item in b}
>>> [item + b_dict.get(item[0], (None, None)) for item in a]
[
    (32, None, 'q', 32, 'dd'), 
    (1, 'f', 'e', 1, 'pp'), 
    (2, 's', 'f', None, None), 
    (7, 'r', None, None, None)
]

由于我们迭代 a 以形成结果列表，并查找第二个列表的值，这将充当 "LEFT JOIN" - 从左侧返回所有项目 "table" 即使它们不在右边 "table".

Answer 2

详情可以选择pandas as a solution. pandas is a python module related with data process, it has MySQL interface and could mock database operation(like filter, join, groupby) in its DataFrame, please check here。

import pandas as pd

# origin data
#a = [(1,f,e),(7,r,None),(2,s,f),(32,None,q)]
#b = [(32,dd), (1,pp)]

# new data
a = [{'a1':1,'a2':'f', 'a3':'e'}, {'a1':2, 'a2':'r', 'a3':None}]
b = [{'b1':32, 'b2':'dd'}, {'b1':1, 'b2':'pp'}]

pd_a = pd.DataFrame(a)
pd_b = pd.DataFrame(b)

result = pd.merge(pd_a, pd_b, left_on='a1', right_on='b1', how='left')
print result

输出如下：

   a1 a2    a3  b1   b2
0   1  f     e   1   pp
1   2  r  None NaN  NaN

Python 相当于 MySQL "Left Join" 两个元组列表

Python equivalent of MySQL "Left Join" two lists of tuples

python

left-join