保留 JPA 模型时出错

Question

我在保存数据时出错，我不知道那里出了什么问题！！

这是Persistence.xml

的内容

    <persistence xmlns="http://java.sun.com/xml/ns/persistence"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
             version="2.0">

    <persistence-unit name="manager1" transaction-type="RESOURCE_LOCAL">

        <properties>

            <!--PostgreSQL-->
            <property name="hibernate.connection.driver_class" value="org.postgresql.Driver"/>
            <property name="hibernate.connection.url" value="jdbc:postgresql://localhost:5432/postgres"/>
            <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/>
            <property name="hibernate.connection.username" value="postgres"/>
            <property name="hibernate.connection.password" value="postgres"/>
            <property name="hibernate.archive.autodetection" value="class"/>
            <property name="hibernate.id.new_generator_mappings" value="true"/>
            <property name="hibernate.hbm2ddl.auto" value="update"/>
            <property name="hibernate.ejb.metamodel.generation" value="disabled"/>
            <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultComponentSafeNamingStrategy"/>
            <property name="hibernate.show_sql" value="true"/>
        </properties>

    </persistence-unit>

</persistence>

这是 Rest 网络服务调用：

@GET
@Path("/")
public Response test() {

    EntityManagerFactory emf = Persistence.createEntityManagerFactory("manager1");
    EntityManager em = emf.createEntityManager();

    Member member = new Member("doux");
    em.persist(member);


    em.close();
    emf.close();

    return Response.status(Response.Status.OK).build();
}

这是我遇到的错误！！ :

message Unknown entity: ca.products.jpa_models.Member

    description Le serveur a rencontré une erreur interne qui l''a empêché de satisfaire la requête.

    exception

    java.lang.IllegalArgumentException: Unknown entity: ca.products.jpa_models.Member
        org.hibernate.jpa.spi.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:1149)
        ca.products.services.RestServices.test(RestServices.java:41)
        sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
        sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
        java.lang.reflect.Method.invoke(Method.java:497)
        com.sun.jersey.spi.container.JavaMethodInvokerFactory.invoke(JavaMethodInvokerFactory.java:60)
        com.sun.jersey.server.impl.model.method.dispatch.AbstractResourceMethodDispatchProvider$ResponseOutInvoker._dispatch(AbstractResourceMethodDispatchProvider.java:205)
        com.sun.jersey.server.impl.model.method.dispatch.ResourceJavaMethodDispatcher.dispatch(ResourceJavaMethodDispatcher.java:75)
        com.sun.jersey.server.impl.uri.rules.HttpMethodRule.accept(HttpMethodRule.java:288)
        com.sun.jersey.server.impl.uri.rules.ResourceClassRule.accept(ResourceClassRule.java:108)
        com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147)
        com.sun.jersey.server.impl.uri.rules.RootResourceClassesRule.accept(RootResourceClassesRule.java:84)
        com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1469)
        com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1400)
        com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1349)
        com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1339)
        com.sun.jersey.spi.container.servlet.WebComponent.service(WebComponent.java:416)
        com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:537)
        com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:708)
        javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
        org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

Answer 1

我找到了解决方案：

我应该在我的 persistence.xml 中将 link 声明为 class，因为它们不属于同一个包！！

<class>ca.products.jpa_models.Member</class>

这是来源：

class : The class element specifies a fully qualified class name that you will map. By default all properly annotated classes and all hbm.xml files found inside the archive are added to the persistence unit configuration. You can add some external entity through the class element though. As an extension to the specification, you can add a package name in the element (eg org.hibernate.eg). Caution, the package will include the metadata defined at the package level (ie in package-info.java), it will not include all the classes of a given package.

保留 JPA 模型时出错

Error while persisting a JPA model

hibernate

jpa

persistence

persistence.xml