用 linq 实现密集排名

Question

使用以下 linq 代码，如何将 dense_rank 添加到我的结果中？如果那太慢或太复杂，那么 rank window 函数怎么样？

var x = tableQueryable
    .Where(where condition)
    .GroupBy(cust=> new { fieldOne = cust.fieldOne ?? string.Empty, fieldTwo = cust.fieldTwo ?? string.Empty})
    .Where(g=>g.Count()>1)
    .ToList()
    .SelectMany(g => g.Select(cust => new {
        cust.fieldOne
    ,   cust.fieldTwo
    ,   cust.fieldThree
    }));

Answer 1

这样做 dense_rank()。根据您的需要更改 GroupBy 和 Order :) 基本上，dense_rank 是对查询的有序组进行编号，因此：

var DenseRanked = data.Where(item => item.Field2 == 1)
    //Grouping the data by the wanted key
    .GroupBy(item => new { item.Field1, item.Field3, item.Field4 })
    .Where(@group => @group.Any())

    // Now that I have the groups I decide how to arrange the order of the groups
    .OrderBy(@group => @group.Key.Field1 ?? string.Empty)
    .ThenBy(@group => @group.Key.Field3 ?? string.Empty)
    .ThenBy(@group => @group.Key.Field4 ?? string.Empty)

    // Because linq to entities does not support the following select overloads I'll cast it to an IEnumerable - notice that any data that i don't want was already filtered out before
    .AsEnumerable()

    // Using this overload of the select I have an index input parameter. Because my scope of work is the groups then it is the ranking of the group. The index starts from 0 so I do the ++ first.
    .Select((@group , i) => new
    {
       Items = @group,
       Rank = ++i
    })

    // I'm seeking the individual items and not the groups so I use select many to retrieve them. This overload gives me both the item and the groups - so I can get the Rank field created above
    .SelectMany(v => v.Items, (s, i) => new
    {
       Item = i,
       DenseRank = s.Rank
    }).ToList();

另一种方法是 Manoj 在 this question 中的回答所指定的 - 但我不太喜欢它，因为从 table.

中选择了两次

Answer 2

所以如果我理解正确的话，密集排名是组的索引，当组被排序时。

var query = db.SomeTable
    .GroupBy(x => new { x.Your, x.Key })
    .OrderBy(g => g.Key.Your).ThenBy(g => g.Key.Key)
    .AsEnumerable()
    .Select((g, i) => new { g, i })
    .SelectMany(x =>
        x.g.Select(y => new
        {
            y.Your,
            y.Columns,
            y.And,
            y.Key,
            DenseRank = x.i,
        }
    );

用 linq 实现密集排名

implement dense rank with linq

c#

linq

dense-rank