C# 将 JSON DynamicObject 分配给 Class
C# Assign JSON DynamicObject to a Class
public class RootObject
{
public List<Result> results { get; set; }
public int result_index { get; set; }
}
...
private void ReadJson()
{
string JsonString = File.ReadAllText(MyJsonFile);
DynamicObject jObject = System.Web.Helpers.Json.Decode(JsonString);
RootObject RO = (RootObject)jObject;
...
}
行:
RootObject RO = (RootObject)jObject;
不正确。如何将 DynamicObject 分配给我的 Class?
您不能将 DynamicObject
分配给类型为 RootObject
的变量,因为类型不是 assignable. Instead, you should deserialize your JSON as a RootObject
to begin with using Json.Decode<T>
:
var RO = System.Web.Helpers.Json.Decode<RootObject>(JsonString);
有关如何反序列化为特定类型的更多示例,另请参阅 How can I parse JSON with C#? and How to Convert JSON object to Custom C# object?。
public class RootObject
{
public List<Result> results { get; set; }
public int result_index { get; set; }
}
...
private void ReadJson()
{
string JsonString = File.ReadAllText(MyJsonFile);
DynamicObject jObject = System.Web.Helpers.Json.Decode(JsonString);
RootObject RO = (RootObject)jObject;
...
}
行:
RootObject RO = (RootObject)jObject;
不正确。如何将 DynamicObject 分配给我的 Class?
您不能将 DynamicObject
分配给类型为 RootObject
的变量,因为类型不是 assignable. Instead, you should deserialize your JSON as a RootObject
to begin with using Json.Decode<T>
:
var RO = System.Web.Helpers.Json.Decode<RootObject>(JsonString);
有关如何反序列化为特定类型的更多示例,另请参阅 How can I parse JSON with C#? and How to Convert JSON object to Custom C# object?。