PHP 在数组中找到相同的记录

Question

我想检测相同的记录，然后更改一条记录的数量并删除其他记录。例如，给定以下数组：

'Cart' => [
    (int) 0 => [
        'size' => '38',
        'code' => '5',
        'qn' => (int) 1
    ],
    (int) 1 => [
        'size' => '37',
        'code' => '5',
        'qn' => (int) 1
    ],
    (int) 2 => [
        'size' => '37',
        'code' => '5',
        'qn' => (int) 1
    ]
],

我要打印：

'Cart' => [
    (int) 0 => [
        'size' => '38',
        'code' => '5',
        'qn' => (int) 1
    ],
    (int) 1 => [
        'size' => '37',
        'code' => '5',
        'qn' => (int) 2
    ]

],

Answer 1

我不知道这是否足以解决您的问题，但请尝试功能 array_unique

Answer 2

迭代数组并在每个子数组上使用 array_diff。如果返回的数组既不包含 size 也不包含 code，请添加两个 qn

Answer 3

函数array_unique()适用于一维数组。要从多维数组中找到唯一元素，我们需要做一点修改。

试试这个：

$array  = array_map("serialize", $array);
$output = array_map("unserialize", array_unique($array));

如果您想采用另一种方法，请使用此方法作为参考：Create multidimensional array unique

Answer 4

在我看来，您正在尝试对重复尺寸 (size) 和代码 (code) 的数量 (qn) 求和。实现此目的的一种方法是遍历包含购物车项目的数组并构建一个新数组。我建议阅读 PHP arrays and array_key_exists 以了解更多，因为它们在下面使用：

<?php

$arr = [
    ['size' => '38', 'code' => 5, 'qn' => 1],
    ['size' => '37', 'code' => 5, 'qn' => 1],
    ['size' => '37', 'code' => 5, 'qn' => 1],
    ['size' => '37', 'code' => 4, 'qn' => 1],
];

$newArr = [];

foreach ($arr as $value) {
    $key = $value['size'] . ':' . $value['code'];

    if (array_key_exists($key, $newArr)) {
        $newArr[$key]['qn'] += $value['qn'];
        continue;
    }

    $newArr[$key] = $value;
}

// Resets keys
$newArr = array_values($newArr);

print_r($newArr);

Answer 5

请完成以下代码。

    $result = [
        0=> ['size' => '38',
                'code' => '5',
                'qn' => 1
            ],
        1=> ['size' => '37',
               'code' => '5',
               'qn' => 1
            ],
        2=> ['size' => '37',
                'code' => '5',
                'qn' => 1
            ]
    ];

$finalArr = [];
foreach($result as $k => $v) {
    $flag = 0;
    foreach($finalArr as $kc => $vc){
        if($v['size']==$vc['size'] && $v['code']==$vc['code']){
            $flag = 1;  
            $finalArr[$kc]['qn']    = $finalArr[$kc]['qn'] + 1;
            break;
        } 
    }
    if($flag==0){
        $finalArr[] = 
        [
            'size'  => $v['size'],
            'code'  => $v['code'],
            'qn'    => 1
        ];
    }       
}
echo "<pre>";
print_r($finalArr);

Answer 6

代码已针对您的问题进行了测试，我已经解释了代码。这为您提供了任意数量的数组和类似数组元素的解决方案，数量（qn）根据需要递增：

<?php
//Compare the 1st and 2nd array
//Compare the 2st and 3rd array
// and so on
function compare($arr1 = array(), $arr2 = array()) {        
    $result = array_diff($arr1, $arr2);  
    return $result;
}

$cart = array(
        0 => array('size' => 38, 'code' => 5, 'qn' => 1),
        1 => array('size' => 37, 'code' => 5, 'qn' => 1),
        2 => array('size' => 37, 'code' => 5, 'qn' => 1),
        );
$j = 1;
$cart_total_count = count($cart);//Gives the count of your cart
$final_cart = array();//Final array with qn incremented
for($i=0;$i<$cart_total_count; $i++) {
    if (!empty($cart[$i+1])) {//If 2nd array is not present then stop the comparision
        if (empty(compare($cart[$i], $cart[$i+1]))){
            $j++;
            $cart[$i]['qn'] = $j;                      
            $final_cart = $cart[$i];            
        }
    }
}var_dump($final_cart);
//Output 
//1. If 2 array are same
//array(3) { ["size"]=> int(37) ["code"]=> int(5) ["qn"]=> int(2) }
//2. If no array are same
//array(0) { }?>

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