Javascript: 通过 lodash 或下划线或 corejavascript 转换对象响应数组
Javascript: Transform array of object response via lodash or underscore or corejavascript
我正在使用 highChart 创建柱形图。我如何通过与数据库通信来创建以下 arrayofObj。
现在,我需要将以下 source
对象数组转换为以下输出。
var source = [
{data: 258, name: '2014'}
{data: 18, name: '2016'}
{data: 516, name: '2014'}
{data: 0, name: '2014'}
{data: 354, name: '2014'}
{data: 18, name: '2016'}
]`
将此对象数组转换为
Output
[{
name: '2014',
data: [258, 516, 354]
}, {
name: '2016',
data: [18, 0, 18]
}]
基本上,我希望我的数组按名称(年份)分组并且数据应该在数组中
这是我应用的解决方案。
var source = [];
_.each(source, function(singlerec) {
source.push({
name: singlerec.name,
data: singlerec.data // Here It only assign single record
});
});
在Lodash中,我总是使用_.groupBy
and then _.map
输出格式。
var source = [{"data":258,"name":"2014"},{"data":18,"name":"2016"},{"data":516,"name":"2014"},{"data":0,"name":"2014"},{"data":354,"name":"2014"},{"data":18,"name":"2016"}];
var output = _(source)
.groupBy('name')
.map(function(v, k) { return { name: k, data: _.map(v, 'data') } })
.value();
console.log(output);
<script src="https://cdn.jsdelivr.net/lodash/4.13.1/lodash.min.js"></script>
有一种方法可以使用 reduce
甚至不用 lodash 来迭代数组一次。
source.reduce((p, n) => {
(p[n.name] || (p[n.name] = [])).push(n.data);
return p
}, {})
我使用纯 javascript 函数:
const pick = (obj, paths) => ({...paths.reduce((a, k) => ({...a, [k]: obj[k]}), {})})
function groupByAndConcat(data, groupBy, sums) {
return data.reduce((results, r) => {
const e = results.find((x) => groupBy.every((g) => x[g] === r[g]));
if (e) {
sums.forEach((k) => e[k] = [].concat(e[k], r[k]));
} else {
results.push(pick(r, groupBy.concat(sums)));
}
return results;
}, []);
}
鉴于您的示例来源:
const source = [
{data: 258, name: '2014'},
{data: 18, name: '2016'},
{data: 516, name: '2014'},
{data: 0, name: '2014'},
{data: 354, name: '2014'},
{data: 18, name: '2016'},
];
console.log(groupByAndConcat(source, ["name"], ["data"]))
输出:
[{ name: "2014", data: Array [258, 516, 0, 354] }, { name: "2016", data: Array [18, 18] }]
也可以对几个props进行分组或操作:
groupByAndConcat(source, ["name","month"], ["data","data2"])
我正在使用 highChart 创建柱形图。我如何通过与数据库通信来创建以下 arrayofObj。
现在,我需要将以下 source
对象数组转换为以下输出。
var source = [
{data: 258, name: '2014'}
{data: 18, name: '2016'}
{data: 516, name: '2014'}
{data: 0, name: '2014'}
{data: 354, name: '2014'}
{data: 18, name: '2016'}
]`
将此对象数组转换为
Output
[{
name: '2014',
data: [258, 516, 354]
}, {
name: '2016',
data: [18, 0, 18]
}]
基本上,我希望我的数组按名称(年份)分组并且数据应该在数组中
这是我应用的解决方案。
var source = [];
_.each(source, function(singlerec) {
source.push({
name: singlerec.name,
data: singlerec.data // Here It only assign single record
});
});
在Lodash中,我总是使用_.groupBy
and then _.map
输出格式。
var source = [{"data":258,"name":"2014"},{"data":18,"name":"2016"},{"data":516,"name":"2014"},{"data":0,"name":"2014"},{"data":354,"name":"2014"},{"data":18,"name":"2016"}];
var output = _(source)
.groupBy('name')
.map(function(v, k) { return { name: k, data: _.map(v, 'data') } })
.value();
console.log(output);
<script src="https://cdn.jsdelivr.net/lodash/4.13.1/lodash.min.js"></script>
有一种方法可以使用 reduce
甚至不用 lodash 来迭代数组一次。
source.reduce((p, n) => {
(p[n.name] || (p[n.name] = [])).push(n.data);
return p
}, {})
我使用纯 javascript 函数:
const pick = (obj, paths) => ({...paths.reduce((a, k) => ({...a, [k]: obj[k]}), {})})
function groupByAndConcat(data, groupBy, sums) {
return data.reduce((results, r) => {
const e = results.find((x) => groupBy.every((g) => x[g] === r[g]));
if (e) {
sums.forEach((k) => e[k] = [].concat(e[k], r[k]));
} else {
results.push(pick(r, groupBy.concat(sums)));
}
return results;
}, []);
}
鉴于您的示例来源:
const source = [
{data: 258, name: '2014'},
{data: 18, name: '2016'},
{data: 516, name: '2014'},
{data: 0, name: '2014'},
{data: 354, name: '2014'},
{data: 18, name: '2016'},
];
console.log(groupByAndConcat(source, ["name"], ["data"]))
输出:
[{ name: "2014", data: Array [258, 516, 0, 354] }, { name: "2016", data: Array [18, 18] }]
也可以对几个props进行分组或操作:
groupByAndConcat(source, ["name","month"], ["data","data2"])