Python 外卡赛

Question

我有这样一个文件

iPhone6-16GB-Black,40000,10000,10000,20000

iPhone6-16GB-White,40000,10000,10000,20000

iPhone6-16GB-Gold,40000,10000,10000,20000

iPhone6-16GB-Silver,40000,10000,10000,20000

iPhone6-16GB-Gray,40000,10000,10000,20000

iPhone6-64GB-Black,40000,10000,10000,20000

iPhone6-64GB-White,40000,10000,10000,20000

我需要逐行搜索并找到与输入匹配的所有行

if input = iPhone6-*-* 它应该匹配所有带有 iPhone6-

的行

if input = iPhone6-16GB-* 它应该匹配所有带有 iPhone6-16GB-

的行

if input = *-*-* 它应该匹配所有行

到目前为止我有这样的代码

for line in devLines:
    line = line.rstrip()
    line = line.strip()
    if line and not line.startswith("#"):
        devName = line.split(",")[0]
        devName = devName.strip()
        if re.search(device, line) :

Answer 1

我想这就是你的意思吧？请更具体。

我使用的文件。 (test.txt)

name-12-100
name-12-200
name-24-100
name-36-100

代码。

from re import search

ipt = 'name-12'

with open('test.txt','r') as f:
    for line in f.readlines():
        if search(ipt, line):
            print line

'name'

name-12-100
name-12-200
name-24-100
name-36-100

'name-12'

name-12-100
name-12-200

'name-12-200'

name-12-200

Answer 2

获取用户的搜索输入。
通过csv模块打开并reader文件。
用搜索文本检查每行的第一项。
打印结果。

代码：

import csv

search_text = raw_input('Enter search text:').strip()

file2 =  '/home/vivek/Desktop/Whosebug/file3.txt'

with open(file2) as fp1:
    root = csv.reader(fp1)
    if search_text=="*":
        result =  list(root)
    else:
        result = [i for i in root  if search_text==i[0]]
        #result = []
        #for i in root:
        #   if search_text == i[0]:
        #       result.append(i)

print result

输出：

Enter search text:*
[['iPhone6-16GB-Black', '40000', '10000', '10000', '20000'], ['iPhone6-16GB-White', '40000', '10000', '10000', '20000'], ['iPhone6-16GB-Gold', '40000', '10000', '10000', '20000'], ['iPhone6-16GB-Silver', '40000', '10000', '10000', '20000'], ['iPhone6-16GB-Gray', '40000', '10000', '10000', '20000'], ['iPhone6-64GB-Black', '40000', '10000', '10000', '20000'], ['iPhone6-64GB-White', '40000', '10000', '10000', '20000']]

vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:iPhone6-16GB-Gray
[['iPhone6-16GB-Gray', '40000', '10000', '10000', '20000']]

vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:test
[]
vivek@vivek:~/Desktop/Whosebug$

通过正则表达式并根据问题修改：

创建搜索文本的正则表达式。

代码：

import csv
import re
import pprint

file2 =  '/home/vivek/Desktop/Whosebug/file3.txt'

def searchText(search_text):
    print "search_text:", search_text
    with open(file2) as fp1:
        root = csv.reader(fp1)
        result = [i for i in root  if re.findall(search_text, i[0])]

    return result

search_text = raw_input('Enter search text:').strip()
#validate input
try:
    tmp1, tmp2, tmp3 = search_text.split("-")   
    search_text = search_text.replace("*", "[^-]*")
    result = searchText(search_text)
    pprint.pprint(result)
except:
    print "wrong search text. *-*-*"

输出：

vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:*-*-*
search_text: [^-]*-[^-]*-[^-]*
[['iPhone6-16GB-Black', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-White', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-Gold', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-Silver', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-Gray', '40000', '10000', '10000', '20000'],
 ['iPhone6-64GB-Black', '40000', '10000', '10000', '20000'],
 ['iPhone6-64GB-White', '40000', '10000', '10000', '20000']]
vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:iPhone6-*-*
search_text: iPhone6-[^-]*-[^-]*
[['iPhone6-16GB-Black', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-White', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-Gold', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-Silver', '40000', '10000', '10000', '20000'],
 ['iPhone6-16GB-Gray', '40000', '10000', '10000', '20000'],
 ['iPhone6-64GB-Black', '40000', '10000', '10000', '20000'],
 ['iPhone6-64GB-White', '40000', '10000', '10000', '20000']]
vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:iPhone6-64GB-*
search_text: iPhone6-64GB-[^-]*
[['iPhone6-64GB-Black', '40000', '10000', '10000', '20000'],
 ['iPhone6-64GB-White', '40000', '10000', '10000', '20000']]
vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:iPhone6-64GB-White
search_text: iPhone6-64GB-White
[['iPhone6-64GB-White', '40000', '10000', '10000', '20000']]
vivek@vivek:~/Desktop/Whosebug$ python 30.py 
Enter search text:iPhone6-*-White
search_text: iPhone6-[^-]*-White
[['iPhone6-16GB-White', '40000', '10000', '10000', '20000'],
 ['iPhone6-64GB-White', '40000', '10000', '10000', '20000']]
vivek@vivek:~/Desktop/Whosebug$

Answer 3

您可以使用 fnmatch.translate，它将 shell 当作通配符，并将它们转换为可与 re.compile 一起使用的正则表达式字符串，以创建可用于过滤您的匹配器结果：

import re
from fnmatch import translate as wc_to_re

search_for = raw_input('Search for: ') + '*'
is_match = re.compile(wc_to_re(search_for), flags=re.I).match
with open('yourfile') as fin:
    for line in filter(is_match, fin):
        print line, # or do something else appropriate?

匹配不区分大小写，因此输入：iphone6-16gb* 将打印以下内容：

iPhone6-16GB-Black,40000,10000,10000,20000
iPhone6-16GB-White,40000,10000,10000,20000
iPhone6-16GB-Gold,40000,10000,10000,20000
iPhone6-16GB-Silver,40000,10000,10000,20000
iPhone6-16GB-Gray,40000,10000,10000,20000

而 iphone6-16gb-g* 将给出：

iPhone6-16GB-Gold,40000,10000,10000,20000
iPhone6-16GB-Gray,40000,10000,10000,20000

Python 外卡赛

Python wild card match

python

wildcard

match