PHP in_array 匹配搜索值到数组列表

Question

我的页面上有一个搜索功能，用户可以在其中搜索美国各州以找到属性。但是，在我的数据库记录中，每个州名称都只设置了缩写。所以我以数组列表格式下载了美国各州的副本。

代码图1

$searchStates = array(
    'Alabama'          =>'AL',
    'Alaska'           =>'AK',
    'Arizona'          =>'AZ',
    'Arkansas'         =>'AR',
    'California'       =>'CA',
    'Colorado'         =>'CO',
    'Connecticut'      =>'CT',
    'Delaware'         =>'DE',
    'Florida'          =>'FL',
    'Georgia'          =>'GA',
    'Hawaii'           =>'HI',
    'Idaho'            =>'ID',
    'Illinois'         =>'IL',
    'Indiana'          =>'IN',
    'Iowa'             =>'IA',
    'Kansas'           =>'KS',
    'Kentucky'         =>'KY',
    'Louisiana'        =>'LA',
    'Maine'            =>'ME',
    'Maryland'         =>'MD',
    'Massachusetts'    =>'MA',
    'Michigan'         =>'MI',
    'Minnesota'        =>'MN',
    'Mississippi'      =>'MS',
    'Missouri'         =>'MO',
    'Montana'          =>'MT',
    'Nebraska'         =>'NE',
    'Nevada'           =>'NV',
    'New Hampshire'    =>'NH',
    'New Jersey'       =>'NJ',
    'New Mexico'       =>'NM',
    'New York'         =>'NY',
    'North Carolina'   =>'NC',
    'North Dakota'     =>'ND',
    'Ohio'             =>'OH',
    'Oklahoma'         =>'OK',
    'Oregon'           =>'OR',
    'Pennsylvania'     =>'PA',
    'Rhode Island'     =>'RI',
    'South Carolina'   =>'SC',
    'South Dakota'     =>'SD',
    'Tennessee'        =>'TN',
    'Texas'            =>'TX',
    'Utah'             =>'UT',
    'Vermont'          =>'VT',
    'Virginia'         =>'VA',
    'Washington'       =>'WA',
    'West Virginia'    =>'WV',
    'Wisconsin'        =>'WI',
    'Wyoming'          =>'WY'
);

案例：

我的客户用来搜索州名，ex: Tennessee 但在我的结果中，它将显示 无记录 由于缩写仅保存在我的数据库中。我想使用这个 $searchStates 的数组列表来匹配我的州缩写列表。我尝试使用 in_array 函数，但它似乎无法正常工作。请参阅我的实际代码。

代码图2

if (in_array( $search, $searchStates )) {

    $property->where(function($query) use ($search) {
        $query->where('property.state','like','%'.$search.'%')
            ->orWhere('property.contact_name','like','%'.$search.'%')
            ->orWhere('property.address','like','%'.$search.'%')
            ->orWhere('property.city','like','%'.$search.'%')
            ->orWhere('property.name','like','%'.$search.'%');
    });

}

目标

我想使用 $searchStates 列表来匹配我的数据库记录（以美国各州的缩写格式），并在我的搜索结果页面中显示正确的输出。

问题

这个 in_array 函数是否有效，还是我应该使用其他函数？我会感谢你的帮助。

Answer 1

在查询中查找usyng的州名缩写形式

if (isset($searchStates[$search])) {
     $search = $searchStates[$search];
     // rest of your code

Answer 2

像这样使用 array_key_exists：

    $searchStates = array(
        'Alabama'          =>'AL',
        'Alaska'           =>'AK',
        'Arizona'          =>'AZ',
        'Arkansas'         =>'AR',
        'California'       =>'CA',
        'Colorado'         =>'CO',
        'Connecticut'      =>'CT',
        'Delaware'         =>'DE',
        'Florida'          =>'FL',
        'Georgia'          =>'GA',
        'Hawaii'           =>'HI',
        'Idaho'            =>'ID',
        'Illinois'         =>'IL',
        'Indiana'          =>'IN',
        'Iowa'             =>'IA',
        'Kansas'           =>'KS',
        'Kentucky'         =>'KY',
        'Louisiana'        =>'LA',
        'Maine'            =>'ME',
        'Maryland'         =>'MD',
        'Massachusetts'    =>'MA',
        'Michigan'         =>'MI',
        'Minnesota'        =>'MN',
        'Mississippi'      =>'MS',
        'Missouri'         =>'MO',
        'Montana'          =>'MT',
        'Nebraska'         =>'NE',
        'Nevada'           =>'NV',
        'New Hampshire'    =>'NH',
        'New Jersey'       =>'NJ',
        'New Mexico'       =>'NM',
        'New York'         =>'NY',
        'North Carolina'   =>'NC',
        'North Dakota'     =>'ND',
        'Ohio'             =>'OH',
        'Oklahoma'         =>'OK',
        'Oregon'           =>'OR',
        'Pennsylvania'     =>'PA',
        'Rhode Island'     =>'RI',
        'South Carolina'   =>'SC',
        'South Dakota'     =>'SD',
        'Tennessee'        =>'TN',
        'Texas'            =>'TX',
        'Utah'             =>'UT',
        'Vermont'          =>'VT',
        'Virginia'         =>'VA',
        'Washington'       =>'WA',
        'West Virginia'    =>'WV',
        'Wisconsin'        =>'WI',
        'Wyoming'          =>'WY'
    );

    if (array_key_exists( $search, $searchStates )) {
        $searchTerm = $searchStates[$search];

        $property->where(function($query) use ($searchTerm) {
            $query->where('property.state','like','%'.$searchTerm.'%')
                  ->orWhere('property.contact_name','like','%'.$searchTerm.'%')
                  ->orWhere('property.address','like','%'.$searchTerm.'%')
                  ->orWhere('property.city','like','%'.$searchTerm.'%')
                  ->orWhere('property.name','like','%'.$searchTerm.'%');
        });

    }

Answer 3

好的，我最终在我的搜索功能中删除了其他 "queries"。因此，我意识到输入不仅会根据我需要搜索的内容匹配关键字，而且还会找到最接近的字符并匹配我在属性结果中的匹配项。这就是我的代码的最终结果。

if (array_key_exists( $search, $searchStates )) {
    $searchTerm = $searchStates[$search];

    $property->where(function($query) use ($searchTerm) {
        $query->where('property.state','like','%'.$searchTerm.'%');
    });
}

我设法选择了这个，而不是第一个，因为每当我在输入字段中输入全名时，都会恢复为缩写。

"Ex. If I type California, after triggered the search, the California will turn to CA inside the search input."

PHP in_array 匹配搜索值到数组列表

PHP in_array match search value to array list

php

laravel-4.2