如何替换数组中的 img url
how to replace img url in a array
我正在从 ulr 获取数据,所以现在想更改图像的 url,我的代码是
@$domain = $_REQUEST['domain'];
function get_dns($url, $curl = true) {
$responseString = '';
if (!$curl) {
$responseString = file_get_contents($url);
} else {
$ch = curl_init( $url );
$options = array(
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => array('Content-Type: text/html', 'User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.95 Safari/537.36') ,
);
curl_setopt_array( $ch, $options );
$responseString = curl_exec($ch);
}
return $responseString;
}
$url ="http://intodns.scriptburn.com/index.php?domain=$domain";
$query = get_dns($url);
preg_match_all('/<!-- BEGIN CONTENT -->(.*?)<!-- END CONTENT -->/s', $query, $content);
echo $content = $content[0][0];
这里我想把<img src="static/images/
替换成<img src="https://www.whoisextractor.in/wp-content/themes/whois/img/
在
的帮助下,我终于得到了自己的解决方案
现在我的代码是
$url ="http://intodns.scriptburn.com/index.php?domain=$domain";
$query = get_dns($url);
preg_match_all('/<!-- BEGIN CONTENT -->(.*?)<!-- END CONTENT -->/s', $query, $content);
$content = $content[0][0];
$content = preg_replace_callback('~<img\ssrc="static/images/~i',
function($m)
{
return sprintf('<img src="https://www.whoisextractor.in/wp-content/themes/whois/img/', urlencode($m[1]), $m[2], $m[3]);
}, $content);
echo $content;
我正在从 ulr 获取数据,所以现在想更改图像的 url,我的代码是
@$domain = $_REQUEST['domain'];
function get_dns($url, $curl = true) {
$responseString = '';
if (!$curl) {
$responseString = file_get_contents($url);
} else {
$ch = curl_init( $url );
$options = array(
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => array('Content-Type: text/html', 'User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.95 Safari/537.36') ,
);
curl_setopt_array( $ch, $options );
$responseString = curl_exec($ch);
}
return $responseString;
}
$url ="http://intodns.scriptburn.com/index.php?domain=$domain";
$query = get_dns($url);
preg_match_all('/<!-- BEGIN CONTENT -->(.*?)<!-- END CONTENT -->/s', $query, $content);
echo $content = $content[0][0];
这里我想把<img src="static/images/
替换成<img src="https://www.whoisextractor.in/wp-content/themes/whois/img/
在
的帮助下,我终于得到了自己的解决方案现在我的代码是
$url ="http://intodns.scriptburn.com/index.php?domain=$domain";
$query = get_dns($url);
preg_match_all('/<!-- BEGIN CONTENT -->(.*?)<!-- END CONTENT -->/s', $query, $content);
$content = $content[0][0];
$content = preg_replace_callback('~<img\ssrc="static/images/~i',
function($m)
{
return sprintf('<img src="https://www.whoisextractor.in/wp-content/themes/whois/img/', urlencode($m[1]), $m[2], $m[3]);
}, $content);
echo $content;