如何在 laravel 的视图中传递对象

Question

我有一组 html 代码，这些代码在 foreach statement 中被调用 views，我正在尝试推送 array of object 以获得观看次数 controller。

以下是我的控制器代码：

public function get_template($id)
{
    $template = Template::findOrFail($id);
    $getplugin = json_decode($template->templatedata);
    $plugins = Plugin::all();
    $userid = $template->user->id;
    return view('nitseditor.test', ['plugins' => $plugins, 'template'=> $template, 'getplugin' => $getplugin, 'userid' => $userid]);
}

在我的 浏览量中 我是这样打电话的：

@foreach($getplugin as $renderer)

   @include('themes.' . $template->theme->name . '.Plugins.' . $plugins->find($renderer)->type . '.' . $plugins->find($renderer)->id, ['content' => $plugins->find($renderer)->userplugins()->whereUserId($userid)->first()->pivot->contents])

@endforeach

Views or HTML code 正在 generated:

<div id="slideshow">
   <div class="revolution-slider">
     <ul>
        <!-- SLIDE  -->
        @foreach($content->slider as $sliders)
           <li data-transition="{{ $sliders->transition }}" data-slotamount="{{ $sliders->slotamount }}" data-masterspeed="{{ $sliders->masterspeed }}">
              <!-- MAIN IMAGE -->
              <img src="{{ URL::asset($sliders->url) }}" alt="">
           </li>
        @endforeach
     </ul>
  </div>
</div>

现在我收到

错误

Trying to get property of non-object (View: C:\wamp\www\NitsEditor\resources\views\themes\Miracle\Plugins\Slider.blade.php) (View: C:\wamp\www\NitsEditor\resources\views\themes\Miracle\Plugins\Slider.blade.php)

在 foreach loop 中执行 diedump 以下代码时：

foreach ($getplugin as $item){

        $plugincontents[] = Plugin::findOrFail($item)->userplugins()->whereUserId($userid)->first()->pivot->contents;

}
dd($plugincontents);

我能够得到 JSON output，其中包含该特定视图的信息。像下面这样：

array:2 [▼
  0 => "{"slider": [{"url": "img/home/bg.jpg", "slotamount": "7", "transition": "zoomin", "masterspeed": "1500"}, {"url": "img/home/bg2.jpg", "slotamount": "7", "transition": "zoomout", "masterspeed": "1500"}, {"url": "img/home/LOMEg.png", "slotamount": "7", "transition": "slidedown", "masterspeed": "1500"}]}"
  1 => "{"logo": {"logolink": "index.html", "logoimage": "img/home/nitseditorlogo.png"}, "pages": [{"pagelink": "index.html", "pagename": "Mysite"}, {"pagelink": "templates.html", "pagename": "Templates"}, {"pagelink": "aboutus.html", "pagename": "About Us"}, {"pagelink": "contactus.html", "pagename": "Contact Us"}]}"
]

请帮帮我。谢谢。

Answer 1

而不是 $getplugin = json_decode($template->templatedata); 使用 $getplugin = json_decode($template->templatedata,true);

Answer 2

好吧，在进行交叉检查时，我开始知道我需要 json_decode 在视图中查看数据。我试过了，得到了结果，

在我的 Views 中，我对数组做了 json_decode，如下所示：

@foreach($getplugin as $renderer)

    @include('themes.' . $template->theme->name . '.Plugins.' . $plugins->find($renderer)->type . '.' . $plugins->find($renderer)->id, ['contents' => json_decode($plugins->find($renderer)->userplugins()->whereUserId($userid)->first()->pivot->contents)])

@endforeach

终于得到了想要的结果。

如何在 laravel 的视图中传递对象

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