如何对加速度计进行编码以使其具有固定的 x 位置

Question

我有一艘根据重力方向移动的船，重力方向由加速度计改变，但我希望它只沿着屏幕的宽度移动（我已经知道该怎么做），但我知道不知道如何将其保持在固定的水平线上。这是我的代码

class GameScene: SKScene {

var manager = CMMotionManager()
var ship = SKSpriteNode()



override func didMoveToView(view: SKView) {
    /* Setup your scene here */


    let shipTexture = SKTexture(imageNamed: "EvadersShipVert2.png")

    ship = SKSpriteNode(texture: shipTexture)

    ship.position = CGPoint(x: CGRectGetMidX(self.frame), y: CGRectGetMidY(self.frame) - 250)

    ship.size = CGSize(width: 90, height: 115)

    shipTexture.filteringMode = SKTextureFilteringMode.Nearest

    ship.zPosition = 2

    ship.physicsBody = SKPhysicsBody(texture: shipTexture, size: CGSize(width: 90, height: 115))

    ship.physicsBody?.dynamic = true

    self.addChild(ship)


    manager.startAccelerometerUpdates()
    manager.accelerometerUpdateInterval = 0.1
    manager.startAccelerometerUpdatesToQueue(NSOperationQueue.mainQueue()) {

        (data, error) in

        self.physicsWorld.gravity = CGVectorMake(CGFloat((data?.acceleration.x)!), CGFloat((data?.acceleration.y)!))


    }






}

提前致谢！

Answer 1

替换

self.physicsWorld.gravity = CGVectorMake(CGFloat((data?.acceleration.x)!), CGFloat((data?.acceleration.y)!))

有

self.physicsWorld.gravity = CGVectorMake(0.0, CGFloat((data?.acceleration.y)!)

所以你不会影响 x 位置

如何对加速度计进行编码以使其具有固定的 x 位置

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