在 C++ 中将两个双数相除
Dividing two double numbers in C++
我有一些 C++ 经验。我写了下面的代码;
#include <iostream>
using namespace std;
double mass_H;
double mass_S;
double Mass;
double S_Space;
double H2S_Conc;
double Conc;
// calculates the molecular mass of H2S, given the molecular mass of each element
void Molecular_Mass()
{
Mass = ((2*mass_H)+(mass_S));
}
void H2S_Concentration()
{
Conc = H2S_Conc/100;
//c = H2S_Conc/1000000;
}
int main()
{
cout << "Welcome to the H2S conversion .\n";
cout << "Please enter molecular mass of Hydrogen: "<<endl; // enter mass of hydrogen
cin >> mass_H;
cout << "Please enter molecular mass of Sulphur: " << endl; // eneter mass of sulpher
cin >> mass_S;
Molecular_Mass();
H2S_Concentration(); // call molecular mass function
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
cout << "Molecular mass of H2S is: " << Mass << "kg/kmol"<< endl;
cout << "Standard space occupied by a kmol at 0 degrees and 1 atm is: "<< S_Space << "Nm^3/kmol" << endl;
cout << "H2S concentration is: " << H2S_Conc << "parts per million, which is a real concentration of: " << Conc <<endl;
问题是当我编译 运行 时,我的 Conc 值为 0。我正在除以两个双打,我认为这不是问题。
我看过 google 并尝试使用浮点数进行转换,但也没有用。
谁能告诉我为什么返回零
p.s 忽略我剩下的蹩脚代码 ;)
在这两行之后调用 H2S_Concentration()
:-
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
它采用默认初始化值 0
,因为您在调用函数之前没有为其分配任何值。
这应该有效:
#include <iostream>
using namespace std;
// ..
int main()
{
// ..
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
// ..
H2S_Concentration(); // call molecular mass function here
//..
return 0;
}
编辑:
根据 πάντα ῥεῖ 的建议,并且由于您正在对它们的值进行硬编码并且不会更改或不会在 运行 时更改这些值,因此建议将两个变量都设置为常量,并使用想要这样的值:
const double S_Space = 22.41; //Nm^3/kmol;
const double H2S_Conc = 292; // ppm v/v;
错误已得到解答,但您可以稍微编辑一下代码。
例如:
float H2S_Concentration()
{
return H2S_Conc/100;
//c = H2S_Conc/1000000;
}
然后在主要
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
Molecular_Mass();
Conc = H2S_Concentration();
我有一些 C++ 经验。我写了下面的代码;
#include <iostream>
using namespace std;
double mass_H;
double mass_S;
double Mass;
double S_Space;
double H2S_Conc;
double Conc;
// calculates the molecular mass of H2S, given the molecular mass of each element
void Molecular_Mass()
{
Mass = ((2*mass_H)+(mass_S));
}
void H2S_Concentration()
{
Conc = H2S_Conc/100;
//c = H2S_Conc/1000000;
}
int main()
{
cout << "Welcome to the H2S conversion .\n";
cout << "Please enter molecular mass of Hydrogen: "<<endl; // enter mass of hydrogen
cin >> mass_H;
cout << "Please enter molecular mass of Sulphur: " << endl; // eneter mass of sulpher
cin >> mass_S;
Molecular_Mass();
H2S_Concentration(); // call molecular mass function
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
cout << "Molecular mass of H2S is: " << Mass << "kg/kmol"<< endl;
cout << "Standard space occupied by a kmol at 0 degrees and 1 atm is: "<< S_Space << "Nm^3/kmol" << endl;
cout << "H2S concentration is: " << H2S_Conc << "parts per million, which is a real concentration of: " << Conc <<endl;
问题是当我编译 运行 时,我的 Conc 值为 0。我正在除以两个双打,我认为这不是问题。
我看过 google 并尝试使用浮点数进行转换,但也没有用。
谁能告诉我为什么返回零
p.s 忽略我剩下的蹩脚代码 ;)
在这两行之后调用 H2S_Concentration()
:-
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
它采用默认初始化值 0
,因为您在调用函数之前没有为其分配任何值。
这应该有效:
#include <iostream>
using namespace std;
// ..
int main()
{
// ..
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
// ..
H2S_Concentration(); // call molecular mass function here
//..
return 0;
}
编辑: 根据 πάντα ῥεῖ 的建议,并且由于您正在对它们的值进行硬编码并且不会更改或不会在 运行 时更改这些值,因此建议将两个变量都设置为常量,并使用想要这样的值:
const double S_Space = 22.41; //Nm^3/kmol;
const double H2S_Conc = 292; // ppm v/v;
错误已得到解答,但您可以稍微编辑一下代码。 例如:
float H2S_Concentration()
{
return H2S_Conc/100;
//c = H2S_Conc/1000000;
}
然后在主要
S_Space = 22.41; //Nm^3/kmol
H2S_Conc = 292; // ppm v/v
Molecular_Mass();
Conc = H2S_Concentration();