PHP 数组 & XML 无法获取所有内容

Question

我想从这个 xml 中获取所有内容：https://api.eveonline.com/eve/SkillTree.xml.aspx

将其保存在 MySQL 数据库中。

但是缺少一些数据...

任何了解 PHP、Array() 和 XML 的人都可以帮助我吗？

这是我获取内容的代码：

<?php

    $filename = 'https://api.eveonline.com/eve/SkillTree.xml.aspx';
    $xmlbalance = simplexml_load_file($filename);
    $skills = array();

    for ($x=0;$x<sizeOf($xmlbalance->result->rowset->row);$x++) {
         $groupName = $xmlbalance->result->rowset->row[$x]->attributes()->groupName;
         $groupID = $xmlbalance->result->rowset->row[$x]->attributes()->groupID;
         for ($y=0;$y<sizeOf($xmlbalance->result->rowset->row[$x]->rowset->row);$y++) {
             $skills[$x]["skillID"] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->attributes()->typeID;
             $skills[$x]["skillName"] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->attributes()->typeName;            
             $skills[$x]["skillDesc"] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->description;
             $skills[$x]["skillRank"] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->rank;
             $skills[$x]["skillPrimaryAtr"] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->requiredAttributes->primaryAttribute;
             $skills[$x]["skillSecondAtr"] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->requiredAttributes->secondaryAttribute;

             $o = 0;
             for ($z=0;$z<sizeOf($xmlbalance->result->rowset->row[$x]->rowset->row[$y]->rowset->row);$z++) {
                 if ($xmlbalance->result->rowset->row[$x]->rowset->row[$y]->rowset->attributes()->name == "requiredSkills") {
                     $skills[$x]["requiredSkills"]["".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->rowset->row[$z]->attributes()->typeID] = "".$xmlbalance->result->rowset->row[$x]->rowset->row[$y]->rowset->row[$z]->attributes()->skillLevel;
                     $o++;
                 }
             }

         }

    }
     echo '<pre>'; print_r($skills); echo '</pre>';

?>

如果你转到 original XML (link)，在第 452 行，你会看到：

  <row groupName="Spaceship Command" groupID="257">

my array (link 中没有显示）...

这是我发现缺少的一件事... 我认为可能还有更多缺失的内容..

为什么？请问如何解决？

谢谢！！！

Answer 1

您总共只会获得 sizeof($xmlbalance->result->rowset->row) 条记录。因为，在您的第二个 for 循环中，您基本上将结果存储在同一个数组元素中，即 $skills[$x]。

试试这个（我也强烈建议你在编写代码时尽可能地懒惰 - 我的意思是懒惰，如果可能的话，避免一遍又一遍地重复/重写相同的代码）：

$filename = 'https://api.eveonline.com/eve/SkillTree.xml.aspx';
$xmlbalance = simplexml_load_file($filename);
$skills = array();    
foreach ($xmlbalance->result->rowset->row as $row)
{
    $groupName = $row->attributes()->groupName;
    $groupID = $row->attributes()->groupID;

    foreach ($row->rowset->row as $subRow) 
    {
        $skill['skillID'] = (string) $subRow->attributes()->typeID;
        $skill['skillName'] = (string) $subRow->attributes()->typeName;
        $skill['skillDesc'] = (string) $subRow->description;
        $skill['skillRank'] = (string) $subRow->rank;
        $skill['skillPrimaryAtr'] = (string) $subRow->requiredAttributes->primaryAttribute;
        $skill['skillSecondAtr'] = (string) $subRow->requiredAttributes->secondaryAttribute;

        foreach ($subRow->rowset as $subSubRowset) 
        {
            if ($subSubRowset->attributes()->name == 'requiredSkills') 
            {
                foreach ($subSubRowset->row as $requiredSkill) 
                {
                    $skill['requiredSkills'][(string) $requiredSkill->attributes()->typeID] = (string) $requiredSkill['skillLevel'];
                }
            }
        }

        $skills[] = $skill;
    }
}
print_r($skills);

PHP 数组 & XML 无法获取所有内容

PHP Array & XML Can't get all content

php

arrays

xml

for-loop

simplexml