未找到 WebApi POST 方法但 GET 有效

Question

我今天试了很多次用POST调用网络api函数（HttpClient.PostAsync) 方法。但不幸的是我不能。只有使用 GET (HttpClient.GetAsync) 方法的调用才能成功。我尝试在网上跟踪许多示例，但总是出现相同的错误。 ("Not Found")

如果有人能帮助我，非常感谢

这是 C# Web API:

[RoutePrefix("NewAreaMap")]
public class NewAreaMapController: ApiController
{
    [HttpPost]
    [ActionName("PostCreateAreaTemp")]
    public AreaTemp PostCreateAreaTemp(double southLatitude, double westLongitude, double northLatitude, double eastLongitude, int countryId, int worldId)
    {
        AreaTemp newTempMap = new AreaTemp();
        //.....
        * * Here is the C# code from client side: * *
            using(var client = new HttpClient())
            {
                client.BaseAddress = new Uri(ConfigurationManager.AppSettings["SrvWebApiPath"].ToString());
                client.DefaultRequestHeaders.Accept.Clear();
                client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
                var values = new Dictionary < string,
                    string > ()
                    {
                        {
                            "southLatitude", southLatitude.ToString()
                        },
                        {
                            "westLongitude", westLongitude.ToString()
                        },
                        {
                            "northLatitude", northLatitude.ToString()
                        },
                        {
                            "eastLongitude", eastLongitude.ToString()
                        },
                        {
                            "countryId", countryId.ToString()
                        },
                        {
                            "worldId", worldId.ToString()
                        }
                    };
                var content = new FormUrlEncodedContent(values);
                HttpResponseMessage response = await client.PostAsync("api/NewAreaMap/PostCreateAreaTemp", content)
                if (response.IsSuccessStatusCode)
                {
                    string jsonData = response.Content.ReadAsStringAsync().Result;
                    newAreTemp = JsonConvert.DeserializeObject < AreaTemp > (jsonData);
                }
        }

GET 调用适用于以下 Url：

HttpResponseMessage response = await client.GetAsync("api/NewAreaMap/GetAreaTemp/?latitudeAreaCenter=7.02&longitudeAreaCenter=9.05");

Answer 1

请尝试将 FromBody 属性与您的操作参数一起使用。

Answer 2

replace your method parameter with object because you are passing full object "content" from the httpclient so in that case you need to use same object here also with [frombody] attribute methodname([FromBody] Content content) define all the properties in one class and use . Hope it will helpful for you.

Answer 3

既然您要发布 JSON，您不妨将其作为对象发送。或者，如果您仍想保留字典和方法的签名，您可以尝试：

var content = new StringContent(JsonConvert.SerializeObject(values),
            Encoding.UTF8, "application/json");

而不是

var content = new FormUrlEncodedContent(values);

这是一个对象示例。

public class SampleObject
{
    public double SouthLatitude { get;  set; }
    public double WestLongitude { get; set; }
    public double NorthLatitude { get; set; }
    public double EastLongitude { get; set; }
    public int CountryId { get; set; }
    public int WorldId { get; set; }
}

并更改您的要求。

using (var client = new HttpClient())
{
    client.BaseAddress = new Uri(ConfigurationManager.AppSettings["SrvWebApiPath"].ToString());
    client.DefaultRequestHeaders.Accept.Clear();
    client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

    var obj = new SampleObject
    {
        SouthLatitude = southLatitude,
        WestLongitude = westLongitude,
        NorthLatitude = northLatitude,
        EastLongitude = eastLongitude,
        CountryId = countryId,
        WorldId = worldId
    };

    // Send it as StringContent.
    var request = new StringContent(JsonConvert.SerializeObject(obj),
        Encoding.UTF8, "application/json");

    HttpResponseMessage response = await client.PostAsync("api/NewAreaMap/PostCreateAreaTemp", request)
    if (response.IsSuccessStatusCode)
    {
        string jsonData = response.Content.ReadAsStringAsync().Result;
        newAreTemp = JsonConvert.DeserializeObject<AreaTemp>(jsonData);
    }
}

以及服务器上的签名。

public AreaTemp PostCreateAreaTemp(SampleObject sampleObject)

或者如果需要：

public AreaTemp PostCreateAreaTemp([FromBody]SampleObject sampleObject)

未找到 WebApi POST 方法但 GET 有效

WebApi POST method not found but GET works

c#

rest

asp.net-web-api2

webapp2