Sql 将 5 分钟的 3 行分组为 15 分钟的一行

Question

我想将 5 分钟的 3 行分组为 15 分钟的单行，如果需要，我可以对第 3 行进行更新。

这是一个例子：

2016-07-29 14:00:00.000     2016-07-29 14:05:00.000
2016-07-29 14:05:00.000     2016-07-29 14:10:00.000
2016-07-29 14:10:00.000     2016-07-29 14:15:00.000
2016-07-29 14:15:00.000     2016-07-29 14:20:00.000
2016-07-29 14:20:00.000     2016-07-29 14:25:00.000
2016-07-29 14:25:00.000     2016-07-29 14:30:00.000
2016-07-29 14:30:00.000     2016-07-29 14:35:00.000
2016-07-29 14:35:00.000     2016-07-29 14:40:00.000
2016-07-29 14:40:00.000     2016-07-29 14:45:00.000
2016-07-29 14:45:00.000     2016-07-29 14:50:00.000
2016-07-29 14:50:00.000     2016-07-29 14:55:00.000
2016-07-29 14:55:00.000     2016-07-29 15:00:00.000
2016-07-29 15:00:00.000     2016-07-29 15:05:00.000

结果应该是：

2016-07-29 14:00:00.000     2016-07-29 14:15:00.000
2016-07-29 14:15:00.000     2016-07-29 14:30:00.000
2016-07-29 14:30:00.000     2016-07-29 14:45:00.000
2016-07-29 14:45:00.000     2016-07-29 15:00:00.000
...

谢谢！ :)

Answer 1

基本上，您希望将每次截断为 15 分钟的间隔并将其用于聚合。像这样：

select distinct dateadd(minute, datediff(minute, 0, col1) / 15 * 15, 0),
       dateadd(minute, datediff(minute, 0, col1) / 15 * 15 + 15, 0)

Answer 2

我使用 UDF 创建动态日期范围。您也可以使用 number/tally table

Declare @Date1 DateTime = '2016-07-29 14:00:00.000'
Declare @Date2 DateTime = '2016-07-30 00:00:00.000'

Select DateR1=RetVal,DateR2=DateAdd(MI,15,RetVal) from [dbo].[udf-Create-Range-Date](@Date1,@Date2,'MI',15) Where RetVal<@Date2

Returns

DateR1                  DateR2
2016-07-29 14:00:00.000 2016-07-29 14:15:00.000
2016-07-29 14:15:00.000 2016-07-29 14:30:00.000
2016-07-29 14:30:00.000 2016-07-29 14:45:00.000
2016-07-29 14:45:00.000 2016-07-29 15:00:00.000
2016-07-29 15:00:00.000 2016-07-29 15:15:00.000
... 
2016-07-29 23:30:00.000 2016-07-29 23:45:00.000
2016-07-29 23:45:00.000 2016-07-30 00:00:00.000

**

The UDF - Notice you can Ranges, Date Part, and Increment are Parameters

**

CREATE FUNCTION [dbo].[udf-Create-Range-Date] (@DateFrom datetime,@DateTo datetime,@DatePart varchar(10),@Incr int)

Returns 
@ReturnVal Table (RetVal datetime)

As
Begin
    With DateTable As (
        Select DateFrom = @DateFrom
        Union All
        Select Case @DatePart
               When 'YY' then DateAdd(YY, @Incr, df.dateFrom)
               When 'QQ' then DateAdd(QQ, @Incr, df.dateFrom)
               When 'MM' then DateAdd(MM, @Incr, df.dateFrom)
               When 'WK' then DateAdd(WK, @Incr, df.dateFrom)
               When 'DD' then DateAdd(DD, @Incr, df.dateFrom)
               When 'HH' then DateAdd(HH, @Incr, df.dateFrom)
               When 'MI' then DateAdd(MI, @Incr, df.dateFrom)
               When 'SS' then DateAdd(SS, @Incr, df.dateFrom)
               End
        From DateTable DF
        Where DF.DateFrom < @DateTo
    )

    Insert into @ReturnVal(RetVal) Select DateFrom From DateTable option (maxrecursion 32767)

    Return
End

-- Syntax Select * from [dbo].[udf-Create-Range-Date]('2016-10-01','2020-10-01','YY',1) 
-- Syntax Select * from [dbo].[udf-Create-Range-Date]('2016-10-01','2020-10-01','DD',1) 
-- Syntax Select * from [dbo].[udf-Create-Range-Date]('2016-10-01','2016-10-31','MI',15) 
-- Syntax Select * from [dbo].[udf-Create-Range-Date]('2016-10-01','2016-10-02','SS',1)

Answer 3

使用递归 CTE..

DEMO HERE

    ;With cte(sdate,edate,maxdate)
    as
    (
    select min(sdate),dateadd(minute,15,min(sdate) ),max(edate) as maxdate from #tt 
    union all
    select dateadd(minute,15,sdate),dateadd(minute,15,edate) ,maxdate
     from 
     cte
     where 
     edate<=maxdate
    )
   select sdate,edate from cte

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