如何生成代码以导出 Dart 中节点的函数？

Question

（我没能在 dart2js 中运行它，所以我在 dart dev 编译器中尝试；但我很乐意回答 dart2j！）。

如果我有test.dart:

void activate() {
  print("activating...");
}

和运行 dartdevc --modules node -o test.js test.dart输出是：

(function() {
  'use strict';
  const dart_sdk = require('dart_sdk');
  const core = dart_sdk.core;
  const dart = dart_sdk.dart;
  const dartx = dart_sdk.dartx;
  const __test = Object.create(null);
  let VoidTovoid = () => (VoidTovoid = dart.constFn(dart.definiteFunctionType(dart.void, [])))();
  __test.activate = function() {
    core.print("activating...");
  };
  dart.fn(__test.activate, VoidTovoid());
  // Exports:
  exports.__test = __test;
})();

这意味着我的函数导出为 __test.activate，但我需要的只是 activate.

我该如何控制它？我的目标是等效于此的 JS：

exports.activate = function() { core.print("activating"); }

Answer 1

这个 isn't currently possible 但我用包装器解决了它：

var extension = require('./dartvsjs/extension.js');

exports.activate = extension.__lib__extension.activate;
exports.deactivate = extension.__lib__extension.deactivate;

如何生成代码以导出 Dart 中节点的函数？

How can I generate code to export functions for node in Dart?

dart

dart2js