阿卡的嘲笑儿童演员

Question

我正在尝试为我的 actor 编写单元测试，但卡在基本模拟上。 PriceAggregateActor 正在使用 akka 持久性，我不想为它传递所有 conf，而是想完全模拟它。

这是我要测试的演员

object CommandPriceActor {
  def apply() = Props(classOf[CommandPriceActor], PriceAggregateActor())
}

class CommandPriceActor(priceAggregateActorProps: Props) extends Actor with ActorLogging {

  val priceAggregateActor = context.actorOf(priceAggregateActorProps, "priceAggregateActor")

所以在我的测试中，我正在尝试做类似的事情：

class CommandPriceActorTest extends TestKit(ActorSystem("test-benefits",
  ConfigFactory.parseString("""akka.loggers = ["akka.testkit.TestEventListener"] """))) with FlatSpecLike with Matchers
  with BeforeAndAfterAll with Eventually{

  class MockedChild extends Actor {
    def receive = {
      case _ => lala
    }
  }

  val probe = TestProbe()
  val commandPriceActor = TestActorRef(new CommandPriceActor(Props[MockedChild]))

我总是得到：

Caused by: java.lang.IllegalArgumentException: no matching constructor found on class CommandPriceActorTest$MockedChild for arguments []

为什么它抱怨 mockedChild？它不应该接受任何构造函数参数。

Answer 1

这是因为 MockedChild 是您测试的儿童演员。缺少的构造函数参数是对测试的引用（它是父 class）。

您有三个选择：

将对 this 的引用传递给 Props
使用Props
使 MockedChild 成为顶级 class（或对象的成员）

选项 1

val probe = TestProbe()
val mockProps = Props(classOf[MockedChild], this)
val commandPriceActor = TestActorRef(new CommandPriceActor(mockProps))

选项 2

val probe = TestProbe()
val mockProps = Props(new MockedChild)
val commandPriceActor = TestActorRef(new CommandPriceActor(mockProps))

选项 3

val probe = TestProbe()
val mockProps = Props(new CommandPriceActorTest.MockedChild)
val commandPriceActor = TestActorRef(new CommandPriceActor(mockProps))

// ....

object CommandPriceActorTest {
  class MockedChild extends Actor {
    def receive = {
      case _ => lala
    }
  }
}

阿卡的嘲笑儿童演员

Mocking child actor in Akka

scala

unit-testing

akka

akka-testkit