将引用包装器的向量转换为 Base class 到 reference_wrapper 的向量到 Derived class 不能动态转换

Question

如题。我在尝试 dynamic_cast

时遇到此错误

cannot dynamic_cast '(& obj)->std::reference_wrapper<_Tp>::get()' (of type 'class MEPObject') to type 'class MEPGene&' (target is not pointer or reference to complete type) genes.push_back(dynamic_cast (obj.get()));

class MEPObject;
class MEPGene;
typedef std::vector<std::reference_wrapper<MEPObject>> MEPObjects;
typedef std::vector<std::reference_wrapper<MEPGene>> MEPGenes;

void dynamicCast(MEPObjects &objects, MEPGenes &genes)
{
    for(const auto &obj: objects)
    {
        genes.push_back(dynamic_cast<MEPGene&> (obj.get()));
    }
}

Answer 1

前向声明是不够的。

需要 MEPGene 的定义（以查看继承）。

将引用包装器的向量转换为 Base class 到 reference_wrapper 的向量到 Derived class 不能动态转换

Transform vector of reference wrapper to Base class to vector of reference_wrapper to Derived class cannot dynamic cast

c++

dynamic-cast

reference-wrapper