我只想要用户 table 行结果

Question

这张图片是我的 MySQL 个桌子。

这些是我的代码。

$buyuser = CHtml::encode($_POST['buyuser']);
            $criteria = new CDbCriteria;
            $criteria->distinct = FALSE;
            $criteria->with = array('addresses'=>array('alias'=>'adres', 'together'=>true),'addresses.city'=>array('alias'=>'city', 'together'=>true));
            $criteria->addCondition('t.name LIKE "'.$buyuser.'%" OR t.name LIKE "% '.$buyuser.'%" OR t.lastname LIKE "'.$buyuser.'%" OR t.lastname LIKE "% '.$buyuser.'%" OR adres.store LIKE "'.$buyuser.'%" OR adres.store LIKE "% '.$buyuser.'%" OR city.name LIKE "'.$buyuser.'%" OR city.name LIKE "% '.$buyuser.'%"');
            $users = Users::model()->findAll($criteria);

它有效，但我还想在 city.name 或姓氏或商店是一个时看到重复的记录。我需要所有地址。

Answer 1

我更改了 findAll 中的基础 table 及其答案。

$buyuser = CHtml::encode($_POST['buyuser']);
        $criteria = new CDbCriteria;
        $criteria->distinct = FALSE;
        $criteria->with = array('user'=>array('together'=>true),'city'=>array('together'=>true));
        $criteria->addCondition('user.name LIKE "'.$buyuser.'%" OR user.name LIKE "% '.$buyuser.'%" OR user.lastname LIKE "'.$buyuser.'%" OR user.lastname LIKE "% '.$buyuser.'%" OR CONCAT(user.name," ",user.lastname) LIKE "'.$buyuser.'%" OR CONCAT(user.name," ",user.lastname) LIKE "% '.$buyuser.'%" OR t.store LIKE "'.$buyuser.'%" OR t.store LIKE "% '.$buyuser.'%" OR city.name LIKE "'.$buyuser.'%" OR city.name LIKE "% '.$buyuser.'%"');
        $addresses = Addresses::model()->findAll($criteria);

我只想要用户 table 行结果

I want just users table rows in result

php

mysql

yii

criteria