如何在 json 数据 laravel 5.1 中查询生成器

Question

如何在json数据中查询生成器？我正在使用 guzzle，我只想要如何查询，比如搜索数量不为 NULL 的数据？

json 数据结果：

{
  "amount": [
    {
      "member_id": "SSD",
      "sum4": null,
      "sum5": null,
      "sum6": null
    },
    {
      "member_id": "OGG",
      "sum4": 122,
      "sum5": 242,
      "sum6": 123
    },
    {
      "member_id": "PUCAN",
      "sum4": 123,
      "sum5": 443,
      "sum6": 222
    },
    {
      "member_id": "SS3TG",
      "sum4": null,
      "sum5": null,
      "sum6": null
    }
  ]
}

我只想知道如何在 JSON 结果中不为空的情况下获取 sum4、sum6、sum6，你们能帮帮我吗..

Answer 1

// Pass JSON data with true as parameters to json_decode function
// It returns value as associative array
$data = json_decode($jsonData, true);

// Loop through amount
foreach($data['amount'] as $sum)
{
    // Check sum is not null
    if ($sum['sum4'] != null) {
        echo $sum['sum4'];
    // Check sum is not null
    } elseif ($sum['sum5'] != null) {
        echo $sum['sum5'];
    // Check sum is not null
    } elseif ($sum['sum6'] != null) {
        echo $sum['sum6'];
    }
}

如何在 json 数据 laravel 5.1 中查询生成器

How to Query Builder in json data laravel 5.1

php

api

json

laravel

guzzle